Hess's Law and change of enthelpy

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The discussion centers on calculating the change of enthalpy for the reaction 2C(s) + O2(g) -> 2CO(g) using Hess's Law. The enthalpy values provided are -393.7 kJ/mol for the combustion of solid carbon to form carbon dioxide and -283.3 kJ/mol for the combustion of carbon monoxide to form carbon dioxide. Initially, there was confusion regarding how to apply Hess's Law to derive the correct reaction equation. After some trial and error, the correct approach was identified: by reversing the combustion reactions and adjusting their enthalpy values accordingly. The final calculation yielded a change in enthalpy of approximately -221 kJ/mol for the reaction, confirming the application of Hess's Law in determining the enthalpy change.
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The enthalpy of combustion of solid carbon to form carbon dioxide is -393.7 kj/mol carbon, and the enthalpy of combustion of carbon monoxide to form carbon dioxide is -283.3 kj/mol CO. Use these data to calculate change of enthalpy for the reaction

2C(s) + O2(g) -> 2CO(g)

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I'm quite lost . . . after trying this problem for about 20 mins now . . . I still don't see how to use Hess's Law to formulate this answer

What i tried to do was to "form" the equations by the words in the problems.

He are my formulations below; however, I can't seem to get the equation mentioned above.

2CO + O2 -> 2CO2
C + O2 -> CO2

when I rearrange these . . . I can't seem to get 2C(s) + O2(g) -> 2CO(g)

the answer is -220 Kj/mol

thanks
 
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EUREKA! I GOT IT :) :)

2 (C + O2 -> CO2) change in Enthalpy = 2(-394) kj/mol
2CO2 -> O2 + 2CO change in Enthalpy = 2(239.3) kj/mol

= 2C + O2 -> 2CO change in Enthalpy = 221 kj/mol + or - 1 kj/mol

:D ;) :)
 
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