- #1
yannguyen
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Nitrogen dioxide reacts with carbon monoxide by the overall equation:
NO2(g) + CO(g) ----> NO(g)+ CO2(g)
At a particular temperature, the reaction is second order In NO2 and zero order in CO. The rate constant is 0.515 L/(mol*s). How much heat energy evolves per second initially from 3.50 L of reaction mixture containing .0250 M NO2?
Assume the enthalpy change is constant with temperature.How much heat energy evolves per second initially from 3.50 L of reaction mixture containing .0250 M NO2?
I figured out the rate law for this = k[NO2]^2
The enthalpy change for NO2 is 33.1 kJ/mol
However I don't really understand how the concentration, the volume, and the rate constant would relate to find out the heat energy?
Should i find the number of moles of NO2 or what should I do? I totally have no idea about this!
Any help would be highly appreciate
NO2(g) + CO(g) ----> NO(g)+ CO2(g)
At a particular temperature, the reaction is second order In NO2 and zero order in CO. The rate constant is 0.515 L/(mol*s). How much heat energy evolves per second initially from 3.50 L of reaction mixture containing .0250 M NO2?
Assume the enthalpy change is constant with temperature.How much heat energy evolves per second initially from 3.50 L of reaction mixture containing .0250 M NO2?
I figured out the rate law for this = k[NO2]^2
The enthalpy change for NO2 is 33.1 kJ/mol
However I don't really understand how the concentration, the volume, and the rate constant would relate to find out the heat energy?
Should i find the number of moles of NO2 or what should I do? I totally have no idea about this!
Any help would be highly appreciate