Classical thermodynamics problem.

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The discussion revolves around a thermodynamics problem involving two identical masses of water at different temperatures, T1 and T2, and the calculation of the global increase in entropy after they reach thermal equilibrium. The initial formula proposed for entropy change was incorrect, leading to confusion. A key point is to consider the equilibrium temperature and the entropy change for each mass of water. After some guidance, the participant realized the correct approach to solve the problem. The conversation highlights the importance of understanding thermal equilibrium and entropy calculations in thermodynamics.
Kalimaa23
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Hm, I'm pretty much stuck on a thermodynamics problem.

If you consider two identical masses of water at temperatures T1 and T2, what is the global increase in entropy after they have reached thermal equilibrium.

The best I could come up with is [del]S = m*C*ln(T2/T1).

The answer listed in the book is 2m*C*ln[(T1+T2)/2Sqrt(T1*T2)]

I am completely and utterly stuck. Any help would be greatly appreciated.

-Dimi
 
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This will probably be moved to HWK. help, but think about what the equilibrium temperature is, and the change in Entropy of each block.
 
Yes, that's it. I've got it. Thanks.
 
If have close pipe system with water inside pressurized at P1= 200 000Pa absolute, density 1000kg/m3, wider pipe diameter=2cm, contraction pipe diameter=1.49cm, that is contraction area ratio A1/A2=1.8 a) If water is stationary(pump OFF) and if I drill a hole anywhere at pipe, water will leak out, because pressure(200kPa) inside is higher than atmospheric pressure (101 325Pa). b)If I turn on pump and water start flowing with with v1=10m/s in A1 wider section, from Bernoulli equation I...

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