How to use complex exponential to find higher derivatives of e^x cos(x√3)?

Click For Summary
SUMMARY

The discussion focuses on using the complex exponential function to find the 10th derivative of the function \( e^x \cos(x\sqrt{3}) \). The key method involves converting the cosine function into exponential form using \( \cos{\theta} = \frac{e^{i\theta} + e^{-i\theta}}{2} \). This transformation simplifies the differentiation process, allowing each successive derivative to add a power to the coefficient of \( e \). Participants confirm that this approach is efficient and avoids tedious calculations.

PREREQUISITES
  • Understanding of complex exponential functions
  • Knowledge of derivatives and differentiation techniques
  • Familiarity with Euler's formula: \( e^{i\theta} = \cos{\theta} + i\sin{\theta} \)
  • Basic proficiency in calculus, particularly in handling trigonometric functions
NEXT STEPS
  • Study the application of Euler's formula in complex analysis
  • Learn advanced differentiation techniques for exponential functions
  • Explore the properties of derivatives of trigonometric functions
  • Investigate the use of complex numbers in solving differential equations
USEFUL FOR

Mathematicians, calculus students, and anyone interested in advanced differentiation techniques, particularly those involving complex numbers and exponential functions.

dcl
Messages
54
Reaction score
0
How would one use the complex exponential to find something like this:
<br /> \frac{{d^{10} }}{{dx^{10} }}e^x \cos (x\sqrt 3 )
I'm guessing we'd have to convert the cos into terms of e^{i\theta } but the only thing I can think of doing then is going through each of the derivatives. I am guessing there is another way?

thanks in advance.
 
Physics news on Phys.org
e^{i \theta} = \cos{\theta} + i\sin{\theta}

so

\cos{\theta} = \frac{e^{i \theta} + e^{-i \theta}}{2}

Then each successive derivative just adds a power to the coefficient of e.

cookiemonster
 
Last edited:
Ahhh, fair enough :)
Thought it was going to be tedious, but isn't nearly that bad..
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 8 ·
Replies
8
Views
904
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K