Recent content by mzh

ahm, yeah heard of it... yes, it's the last step of the equation that I'm struggling with. I guess my conceptual problem is that to me the term substitution of variables when calculating integrals involves some sort of u(x) = 2x mechanism when calculating the integral \int \sin 2x dx.

Hello. That's right, g(E) is the state density. But what I still don't see is how the substitution k\rightarrow E is being made.

@Ilmrak. Thanks for the reply... ok, so what's the motivation for introducing g(E)? And, how to come up with the definition of g(E)?

Hi I'm looking for a book of which I can't remember exactly the title or the author. It was something along the lines of "Introduction to IC design and applications" "Basic IC theory" by a guy called XYZ *son, I think. It's a little black book from somewhen around 1979 or so. I remember...

Hey, I'm running a semi-quantitative simulation and I have a surface charge densitiy of 10 electrons per square nanometer. Is this anything realistic? The surface is immersed in an electrolyte so the total charge is canceled by ions from the solution. But still, can I pack 10 e's on such a...

You're partially confused. The Fermi level is the energy of a hypothetical state with probability of being occupied equal 50%. To realize this, you need to consider the Fermi distribution function f(E) which tells you how probable it is that a state is occupied. You will realize that under...

Remember that all is governed by quantum mechanics, meaning that the energy of the electrons is discrete. Initially, the electron populates a quantum mechanical state k (eigenfunction of the Hamilton operator, also called orbital) and when it jumps to the conduction band (into another orbital it...

@mfb: thanks. i would think the same. something must be fishy with my simulation then.

Sure. I'll see what I get when considering the intensity. To return to my main point of the thread (i'm not so much interested in how correct my simulation is done or not). Given the above system (surface charge on R1, metallic R2). What will the field look like, say from textbook...

Thanks guys for the feedback. @mfb: Ok. And can it also terminate on induced charges? @{jtbell,AJ Bentley}: that's exactly what i was expecting. In the simulator, R2 is assigned a "metal" property. But I don't know if it can plot the actual charge distribution. Yeah, did not show the intensity...

Dear Physics Forums readers Let a two dimensional rectangle R1 carry a surface charge \sigma and be placed next to another rectangle R2 of the same shape made from metal (i.e. a conductor). What does the electric field look like close to the second rectangle? My intuition would tell me, the...

I think I found the solution to this. The important point to note is that we assume relatively high temperatures. Given the relationship for N_D^+ = \frac{N_D}{1+2\exp\left[\frac{E_F - E_D}{kT}\right]}, we can assume that E_F - E_D is much lower than zero. Then, when dividing by kT = 0.025...

Dear PF users Would be great if somebody could point me out how to arrive at n_{n0} = \frac{1}{2} \left[ (N_D - N_A) + \sqrt{ (N_D - N_A)^2 + 4n_i^2} \right] (n-type charge carrier concentration at thermal equilibrium) by using the expression for the charge neutrality n+N_A = p+N_D and the mass...

you're saying it does not make sense, because the vacuum is not polarizable.. why do i need to measure the dielectric constant of ice depending on frequency? can I not just insert a block of ice between two electrodes and apply a potential to one side? From C = \epsilon_r \epsilon_0...

Thanks for your comment, however I don't understand it: What is the difference between free space and vacuum formally? Do you agree to the statement that polarization arises from the response of a polarizable material to an electric field, i.e. the dipole moments of the material (built-in or...