Recent content by physicsnewby

not sure if this is right, y = y0 + Vo sin t - 1/2gt^2 0 = 125 + 65 sin 37 - 4.9t^2 0 = 125 + 39.1 - 4.9t^2 through quadratic equation, t= 10.4s is time for projectile to hit ground X= Xo +XVo t +1/2at^2 X = 0 + 65 cos 37 (10.4) X = 540m (the distance projectile lands from base of cliff) a =...

Once I find the final velocity, how does that help me find the component of velocity if I don't have an angle?

I am drawing a blank. I only thought you needed the init. velocity and then multiply by cos theta for one component and by sin theta for the other. Using the final impact velocity and then doing cos and sin would make sense, but I don't know what angle to use. I guess I somehow need to find...

ah, good question! At impact, I'm not sure what the angle is. From the picture it looks like its almost 90 degrees, but I'm pretty sure that can't be.

I'm using 37 degrees because it was the angle in the question. There is a diagram in my text which I am also using for this. What angle should I be using? I'm not sure what else to use. Thanks

The question does mention the incline - no angle. It could be wrong solving for the vertical spring, you're right. If I solve for horizontal, how would I change it? I know you still need KE, PE and the equation 1/2kx^2

Is this right? maximum spring compression: ball touches spring = spring compresses 1/2mv^2 + mgy + 1/2ky^2 = 1/2mv^2 + mgY + 1/2kY^2 1/2mv^2 + mgY + 0 = 0 + mgY + 1/2(10)Y^2 1/2(10)(6.3)^2 +(10)(9.8Y) = (10)(9.8Y) +1/2(0.1)Y^2 198 +98Y= 98Y + 0.05Y^2 0 = 0.05Y^2 - 198

I've often had problems with these questions. When I put a value in for acceleration, my teacher always circles it and says there should be no acceleration when solving for distance X, so I get confused alot! I know I've got the right answer, but want to know how to correct this other...

Hmmm, I didn't think of that. That said, I'm still not sure where the -63.1 is coming from. If its when the object hits the ground, then the Y component would be zero then, wouldn't it?

Homework Statement An object of mass 10kg is at rest at the top of a frictionless incline. The mass is 2m higher than the elastic spring (k=10 N/cm). What is the objects maximum speed? What is the maximum spring compression? I think I may have got the answers but I'm not sure. Can someone...

This is the exact question: A projectile is shot from the edge of a cliff 125m above ground level with an initial speed of 65m/s at an angle of 37 degrees. Determine the horizontal and vertical components of its velocity.

For Question 2 using the formula you gave, then Vavg = delta X/ delta t 2 = delta X / 0.82 delta X = 1.64m I got the same answer, but my original equation was all wrong. X = 0 + (2)(0.82) +1/2(o)^2 with correct numbers X = 0 + (4)(0.82) +1/2(4.9)^2 X = 3.28 + 12.01 X = 15.29m...

Question 1 is then answered. Question 2, if I need avg. speed: V avg = Vf + Vo / 2 V avg = 0 + 4 / 2 V avg = 2 X = Xo + Vot + 1/2at^2 X = 0 + (2)(0.82) +1/2(o)^2 X = 1.64m

Homework Statement I have to find the x and y components of velocity. I'm given the original velocity of 65 m/s and the projectile is shot at an angle of 37 degrees. Homework Equations X component: Vx cos theta Y component: Vy sin theta The Attempt at a Solution X component...

ok, then to get acceleration, would I use: a = g sin theta a = 9.8 sin 30 a = 4.9 m/s^2 then to solve for time: Vf= Vo - at 0 = 4 - (4.9)t t = 0.82 s