Representing a function as a power series

grothem
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Homework Statement


Evaluate the indefinite integral as a power series and find the radius of convergence

\int\frac{x-arctan(x)}{x^3}


I have no idea where to start here. Should I just integrate it first?
 
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Sure, you could do that. But, I think what they want to do is expand arctan(x) as a power series around 0 and then integrate.
 
ok. So arctan(x) = \int\frac{1}{1+x^2}
= \int\sum (x^(2*n))
= \sum\frac{x^(2(n+1)}{2(n+1)}

is this what you mean?
 
That's one way to get a series for arctan, yes. But you forgot a (-1)^n factor. The expansion of 1/(1-x) has all plus signs. 1/(1+x) doesn't.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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