What is the concentration of the HCl solution?

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To determine the concentration of hydrochloric acid (HCl) in a beaker, 10 mL of HCl is neutralized by 10.5 mL of sodium hydroxide (NaOH) with a concentration of 0.1 mol/dm³. The calculation begins by converting the volume of NaOH used into liters, resulting in 0.0105 L. The moles of NaOH are calculated as 0.0105 L multiplied by 0.1 mol/L, yielding 1.05 x 10^-3 moles of NaOH. Since the neutralization reaction between NaOH and HCl occurs in a 1:1 ratio, the moles of HCl are also 1.05 x 10^-3. Finally, to find the concentration of HCl, the moles of HCl are divided by the volume of HCl in liters (0.01 L), resulting in a concentration of 0.105 mol/L.
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I need to return an asignment today and i just can't figure it out (should be a piece of cake for the people that hangs around here)

There is 10ml HCl with an unknown concentration i a beaker. You let NaOH with the concentration 0,100 mol/dm3 drip into the acid until it is neutralized.
It takes 10,5ml NaOH to neutralize the acid.

With this you should be able to calculate the concentration of the acid or so my teacher say. And all i can do is sit here and look dumb while my brain refuses to cooperate

Could anyone help me i would owe you a life debt. If i don't get this in today i won't get a grade in chemistry
 
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I have posted hint at https://www.physicsforums.com/showthread.php?s=&postid=115160#post115160
 
10.5mL is 0.0105L

mols of NaOH:
0.0105L x 0.1mol/L = 1.05 x 10^-3 mols NaOH

mols of HCl:
1molHCl/1molNaOH * 1.05 x 10^-3 mols NaOH = 1.05 x 10^-3 mol HCl

concentration:
(1.05 x 10^-3 mol HCl) / 0.01L = 0.105 mol/L
 
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