A problem with the standard solution of the two envelopes paradox
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Dec16-06, 04:06 PM
That's not right; this computes the expected value of
A = a
. Or, notationally,
E(B | A = a) = P(B=2A|A=a) * 2a + P(2B=A|A=a) * a/2
true that E(B) = E(A).
OK, thanks for pointing that out. I allowed myself to use my old sloppy terminology in the reply to Matt that I just posted, but I won't do that again.