- #1
giladsof
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Which Way Is V? Understanding the Relationship Between Electricity and Magnetism
- Thread starter giladsof
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- #2
ideasrule
Homework Helper
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You're trying to calculate the current induced by the movement of the rod. That current is 0 when the rod is at equilibrium, because the rod wouldn't be moving. Even when it's not at equilibrium, the induced current is usually so small as to be negligible compared to the current supplied by the power source.
So you just need to consider the force applied by the magnetic field on the rod, due to the existing current I. There's no need to consider induction.
So you just need to consider the force applied by the magnetic field on the rod, due to the existing current I. There's no need to consider induction.
- #3
giladsof
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OK... As I try your idea I get into the following dilemma: which way is V? The movement of the rod or the movement of the current?
Unfortunately neither one of those options creates a force upwards using the right hand rule... \:
Unfortunately neither one of those options creates a force upwards using the right hand rule... \:
Hi,
I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem.
Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$
Where ##b=1## with an orbit only in the equatorial plane.
We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$
Ultimately, I was tasked to find the initial...
Boundary conditions:
The derived Dirichlet and Neumann boundary conditions
In terms of the magnetic scalar potential:
The value of H equals ## 10^{3}## in natural units,
According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##,
## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units.
So is this conversion correct?
Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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