Numerical Analysis: Uniform Continuity Question

The_Stix
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This isn't so much of a homework problem as a general question that will help me with my homework.

I am supposed to prove that a given function is uniformly continuous on an open interval (a,b).

Since for any continuous function on a closed interval is uniformly continuous, I am curious if I can prove that the function is uniformly continuous on [a,b], then it is also uniformly continuous on (a,b).

Thanks!
 
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The_Stix said:
This isn't so much of a homework problem as a general question that will help me with my homework.

I am supposed to prove that a given function is uniformly continuous on an open interval (a,b).

Since for any continuous function on a closed interval is uniformly continuous, I am curious if I can prove that the function is uniformly continuous on [a,b], then it is also uniformly continuous on (a,b).

Thanks!

Yes.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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