somasimple said:
If the membrane is permeable, at rest, to K+ there is an excess of K+ outside the cell. The Na+ ions will encounter them firstly when the membrane will change its state?
The membrane has negligible/leaky permeability to K+ at rest. K+ permeability increases
AFTER the influx of Na+
Also if the membrane is fully permeable to K+ then it won't be at the resting membrane potential. K+ will move out as it is less concentrated outside the cell, this efflux causes hyperpolarization of the cell (decreasing voltage below resting potential V
r).
as "
aytell" stated already there are 2 forces at work.
One caused by the the concentration gradient, the other by the voltage (charge difference).
There are a sequence of events happening.
1. Some stimulus (light/acoustic/mechanic/ligand/etc) mediated voltage increase causes threshold level voltage.
2. At this threshold Na+ channels are frequently open and allow influx from outside (positive
and high in Na+ concentration) to the inside (negative and low in Na+ concentration). This
known as the
rising portion of the action potential (also called
depolarization)
3. Increasing voltage due to Na+ influx triggers the opening voltage gated K+ channels, resulting in a net efflux of K+ from the cell. Against its electrical gradient (- to +) and towards its concentration gradient (high to low concentration). The concentration gradient dominates over the electrical gradient in this circumstance, resulting in the falling phase of
the action potential and slight hyperpolarization.
The movement of ions is determined by the Goldman equation. It is the net sum
that determines the fate of all ion movements.