Converting equations in Natural units to SI?

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To convert equations from natural units (where hbar = c = 1) to SI units, one can multiply by appropriate powers of hbar and c to achieve the correct units. For instance, to convert 1 MeV to mass, use the relation 1 MeV/c^2, and for time, use hbar/MeV. When dealing with dispersion relations, terms involving k^2 can be multiplied by hbar^2, while linear terms in k require careful consideration of units. Specifically, for a term with units of 1 eV of inverse length, multiplying by hbar*c is appropriate. Understanding these conversions is crucial for accurately plotting energy versus momentum in SI units.
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How can I convert an equation in units where hbar = c = 1 into an equation with hbar and c in SI units? I searched around a bit and wasn't able to find anything (I'm probably not asking the right question). Is there some general way to do it rather than just intuition from having seen the equations before with hbar and c in them?
 
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Simply multiply the value with appropriate powers of hbar and c to get the correct unit.

You have 1MeV as a result and want a mass? It is 1MeV/c^2. You have 1/MeV as result and want a time? It is hbar/MeV. And so on.
 
I have a dispersion relation that involves some constants (and it's in natural units so no c or hbar shows up). I'd like to plot E versus k using this equation with k and E in SI units.
There are some terms with k^2/(2m) so I can just multiply those by hbar^2, but then there's another term that is only linear in k which I don't know what to do with. I would like to be able to multiply it by some combo of hbar and c but I have no way of knowing whether it's right. So I have a term that is in units of 1eV of inverse length, what do I multiply by? hbar*c?
 
if you have [k/m] = 1/(m*kg), this is not equivalent to an energy with hbar=c=1.
Or do you have a simple k? Well, [k]=1/m, so [k*hbar*c]=1/m Js m/s = J.
Correct, multiply by hbar*c.
 

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