Ligands and lowering reduction potential

AI Thread Summary
Binding metal cations like Iron (III) and Manganese (II) to anionic ligands can lower their reduction potentials, enhancing their ability to act as reductants. This occurs because the anionic charge of the ligand stabilizes the positive charge of the metal ions, making them more favorable for electron donation. Additionally, if the ligand has a high coordination number (5 or 6), the overall complex may acquire a negative charge, further facilitating electron donation. The concentration of free metal ions is crucial, as it influences the reaction dynamics, and the Nernst equation can be applied to quantify these effects. The discussion references Cytochrome P450 as an example of this phenomenon in action.
Chickenpoxpie
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Hi I have a question I was wondering if y'all could clear up. Let's say I have two metal cations, Iron (III) and Manganese (II). Will binding them to an anionic ligand lower their reduction potentials (making each a better redundant) and if so why?

Is it because the anionic charge of the ligand stabilizes the positive charge of the metals?

What if the ligand binds with a high coordination number (say 5 or 6). Will that further reduce the reduction potential because now the entire complex has a negative charge and is better able to donate electrons (ie good reluctant)?
 
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Basically it is about the concentration of the free metal. You can safely assume what is happening is that it is free metal that reacts, and ligands just change its concentration. Once you know the concentration, it is just a matter of applying Nernst equation.
 
Chickenpoxpie said:
Hi I have a question I was wondering if y'all could clear up. Let's say I have two metal cations, Iron (III) and Manganese (II). Will binding them to an anionic ligand lower their reduction potentials (making each a better redundant) and if so why?

Is it because the anionic charge of the ligand stabilizes the positive charge of the metals?

What if the ligand binds with a high coordination number (say 5 or 6). Will that further reduce the reduction potential because now the entire complex has a negative charge and is better able to donate electrons (ie good reluctant)?

Yes, that's exactly how it works. Read up on Cytochrome p450 and you will see this effect in action.
 
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