Iodide Oxidation by Hydrogen Peroxide

AI Thread Summary
The discussion focuses on the preparation of various chemical solutions and the subsequent mixing of these solutions for a lab experiment. The solutions prepared include a Buffered Iodide Solution, a 0.025M Thiosulfate Solution, and a Peroxide Solution, each with specific volumes and concentrations. Four mixtures are created by combining these solutions in different ratios, followed by cooling them in ice water before adding the peroxide solution. The main inquiry revolves around calculating the moles of sodium thiosulfate reacted in each trial and determining the concentration of thiosulfate in the final 200 mL solution. The calculation method involves using the definition of concentration and applying it to the prepared solutions, emphasizing the importance of accurate calculations rather than guessing.
buzzingbee
Messages
3
Reaction score
0
In my chemistry lab we prepared the following solutions:
Buffered Iodide Solution
25 mL acetic acid/sodium acetate buffer
6mL of 0.5 % starch solution
6 mL of 1.0M KI
fill to the 250 mL mark with distilled water

0.025M Thiosulfate Solution
5 ml of 1 M Na2S2O3
fill to the 200 ml mark with distilled water

Peroxide Soution
30ml of 1 M H2O2
fill to the 150 ml mark with distilled water

Then mixing these solutions together:
Mixture 1:
Buffered Iodide 40ml
Thiosulfate Solution 10ml
Distilled Water 10 ml

Mixture 2:
Buffered Iodide 40ml
Thiosulfate Solution 10ml
Distilled Water 20ml

Mixture3:
Buffered Iodide 40ml
Thiosulfate Solution 10ml

Mixture 4:
Buffered Iodide 40ml
Thiosulfate Solution 5 ml
Distilled Water 5ml

Separately put each beaker into ice water and measure the following amounts of peroxide solution separately into the container of ice:
Mixture 1: 20ml
Mixture 2: 10ml
Mixture 3: 30ml
Mixture 4: 30ml
when the two flasks have cooled on ice below 3°C add the peroxide
time as soon as you add peroxide into the flask

I am unsure for my lab questions what values to use for each trial to calculate the moles of sodium thiosulfate reacted? and how to calculate the mol/L H2O2 reacted
 
Chemistry news on Phys.org
Strangest lab I've ever seen.
 
buzzingbee said:
0.025M Thiosulfate Solution
5 ml of 1 M Na2S2O3
fill to the 200 ml mark with distilled water

How many moles of thiosulfate in 5 mL of 1M solution?

What is the concentration of solution that contains this number of moles of thiosulfate in 200 mL?
 
wouldn't the concentration be 1 M
 
No. Don't guess, try to calculate, following exactly questions as I listed them. This is mostly a simple plug and chug - use the definition of the concentration rearranged to isolate thing that you want to calculate.
 
I want to test a humidity sensor with one or more saturated salt solutions. The table salt that I have on hand contains one of two anticaking agents, calcium silicate or sodium aluminosilicate. Will the presence of either of these additives (or iodine for that matter) significantly affect the equilibrium humidity? I searched and all the how-to-do-it guides did not address this question. One research paper I found reported that at 1.5% w/w calcium silicate increased the deliquescent point by...
I was introduced to the Octet Rule recently and make me wonder, why does 8 valence electrons or a full p orbital always make an element inert? What is so special with a full p orbital? Like take Calcium for an example, its outer orbital is filled but its only the s orbital thats filled so its still reactive not so much as the Alkaline metals but still pretty reactive. Can someone explain it to me? Thanks!!
I'm trying to find a cheap DIY method to etch holes of various shapes through 0.3mm Aluminium sheet using 5-10% Sodium Hydroxide. The idea is to apply a resist to the Aluminium then selectively ablate it off using a diode laser cutter and then dissolve away the Aluminium using Sodium Hydroxide. By cheap I mean resists costing say £20 in small quantities. The Internet has suggested various resists to try including... Enamel paint (only survived seconds in the NaOH!) Acrylic paint (only...
Back
Top