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Could there be an edge to the Universe? |
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| Dec10-07, 04:17 PM | #69 |
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Could there be an edge to the Universe?If it is launched at just below escape velocity it will eventually fall back to Earth and there will be a maximum altitude that it will reach. If launched at above escape velocity it will carry on into 'outer space' to infinity always at some positive velocity. If launched at exactly escape velocity it will be "slowing to zero after an infinite amount of time", yet it will still reach an infinite altitude but asymptotically approaching zero velocity as it does so. That is it will reach 'inifinity' and take an 'infinite' amount of time to do so! The really significant point is that its velocity will only approach zero at 'infinity', i.e. it will never actually do so, it will go on and on to infinity at slower and slower velocity but never reach zero velocity wrt the Earth. I repeat my question, "What (observational) evidence do you have for the hypothesis of the existence of a boundary?" Garth |
| Dec10-07, 05:09 PM | #70 |
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Also, a related question: Even if in cases when Omega=1 the Universe has no maximum volume, is there any value for Omega for which the Universe will (1) stop expanding (like in Omega=1), and (2) have a finite maximum volume? Thanks. At worst, we might say that since both the bounded case and unbounded case have no empirical evidence weighing one way or the other (which apparently is true in practice, and what I've been wondering throughout the thread), we need to choose one model on other grounds (e.g. Occam's razor). My intuition, as discussed here and elsewhere, is that the bounded model is simpler, more common sensical, and less 'faith based'. |
| Dec10-07, 05:22 PM | #71 |
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You don't have to accept that the universe obeys the cosmological principle on scales beyond what we can see to accept the mainstream cosmological model, but I think the issue of which is "simpler" boils down to the number of free parameters needed in the model. In this regard, we are always drawn to the cosmological principle. |
| Dec10-07, 05:38 PM | #72 |
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| Dec10-07, 05:53 PM | #73 |
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Furthermore, the cosmological principle can be tested empirically within our observable universe. Beyond this, we can't test any theory -- for all we know gravity and electromagnetism are completely different outside of our observable universe. Does this mean that the law of gravity cannot be tested empirically? It's not clear to me that you understand the problem fully enough to be reaching such sweeping conclusions. If you're confused about something, please ask. This forum is primarily designed to have experts answer the questions of non-experts, not for the formulation of personal theories. Please be careful that this does not turn into one. |
| Dec10-07, 05:55 PM | #74 |
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Personally the most authoritative and recent source I know is March 2006 http://arxiv.org/abs/astro-ph/0603449 Everybody cites it----it's the official implications for cosmology part of a multipaper series reporting the 3rd year data from the WMAP satellite. If you look on page 50, caption to figure 17, you see a 68 percent errorbar for Omega which is [1.010, 1.041] The errorbar is based on combined data from four major projects: WMAP CMB, supernova, the Sloan digital sky survey, and the 2-degree-field galaxy redshift survey. As of 2006 that was about as good as it gets, and I haven't seen anything since then that is more highly cited. To me that 1.01 is not SURPRISINGLY close to one. Reasons have been offered why, if the universe is spatially S^3, one would nevertheless expect it to be very expanded and so have a small curvature----to be near flat in other words. The errorbar being close to one is not especially remarkable. What is remarkable IMO is that it does not contain one---it is all on the upside. So what [1.010, 1.041] says to me personally is that they already HAVE an errorbar that says S^3, they just don't have enough confidence on it. 68 percent is not enough to disfavor the infinite R^3 case. So I could conclude something if I saw a similar errorbar like [1.010, 1.041] and it had 95 percent confidence. There are technical issues about how you interpret. Like this particular figure assumes dark energy had constant pressure/volume ratio, but they let the constant ratio take on various values. And people can argue should they have allowed time-varying dark energy, or maybe should they have forced the ratio to always be exactly one etc etc. But the technical details don't change the overall sense I get that nowadays the Omega errorbar tends to be mostly over to the > 1 side-----saying "nearly but not exactly" flat. And that the confidence is not high enough to reject the flat case, so one says it is still "consistent with the data" (i.e. flat is not ruled out.) |
| Dec10-07, 05:58 PM | #75 |
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Recognitions:
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The point is that if our model describes an infinite Universe, whereas in fact we are in a Universe that is very very big (much bigger than the observable Universe) then the model works perfectly well. If in the future we discovered the Universe was in fact finite, but much much bigger than the observable Universe we would for most cases simply use the infinite model, since the difference between the two is vanishingly small and the calculations are easier in the infinite model. We do things like this all the time, for instance we think General Relativity is the true theory or gravity, however we usually use Newtonian gravity for most things since the Newtonian model is simpler and easier to work with and the two models give the same answer for most questions we have. This is how science works, we seek to find models that match what we observe, described in the simplest way possible, rather than making metaphysical statements about the extent of reality. If the infinite model works we'll use it, it doesn't matter if whether or not the Universe is truly infinite, that's not the point of the assumption or the model. |
| Dec10-07, 06:08 PM | #76 |
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[tex]a(t) = a(t_0)(\frac{t}{t_0})^{\frac{2}{3}}[/tex] and so as [itex]t \rightarrow \infty[/itex] so [itex]a(t) \rightarrow \infty[/itex]. [itex]\Omega[/itex] > 1. However, with the present understanding of DE the universe will continue to expand, and accelerate in its expansion, even if [itex]\Omega[/itex] > 1. What type of boundary are you thinking of anyway? Garth |
| Dec10-07, 06:14 PM | #77 |
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| Dec10-07, 06:22 PM | #78 |
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Thanks, Garth--this is really helpful.
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| Dec10-07, 06:30 PM | #79 |
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| Dec10-07, 06:40 PM | #80 |
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| Dec10-07, 07:02 PM | #81 |
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Mentor
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Any review papers you can suggest will be appreciated! |
| Dec10-07, 08:41 PM | #82 |
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I am a scientist by trade, so I know how the process works. Discussion here is much more pedagogical, but the basic mode of discourse is the same. If what you have to say is supported by scientific research and/or general knowledge, then say it and present your support. If not, then you can either ask about it or keep it to yourself.[/QUOTE]
AMEN to that! |
| Dec10-07, 08:57 PM | #83 |
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Inflation and Eternal Inflation |
| Dec10-07, 08:57 PM | #84 |
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But The universe has at least 4 dimensions by the most conservative estimate and 11 or 12 dimensions as the normally accepted Number. S or R =3?
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| Dec10-07, 09:15 PM | #85 |
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Also, I am not presenting a theory here. This you must understand. I am asking about the justificatory basis of your theory (viz. the infinite Universe). If you have a sound argument, you should be able to present it without difficulty. I'm simply asking for clarification and pointing out lacunae if I see them. It is sometimes good to have a logician looking over your back, don't you think? |
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