What is the instantaneous speed of a bicycle at the 5m mark during a sprint?

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The discussion revolves around calculating the instantaneous speed of a bicycle at the 5m mark during a sprint, given that it takes 4 seconds to travel 10m with constant acceleration. The initial speed is 0 m/s, and the calculated acceleration is 1.25 m/s². The error in the initial attempt was using the total time for 10m instead of determining the speed at the 5m mark. Correct application of the equations reveals that the instantaneous speed at 5m is 3.5 m/s. The conversation emphasizes the importance of using the correct time interval for accurate calculations.
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Homework Statement


Two physics students are trying to detemine the
instantaneous speed of a bicycle 5.0 m from the
start of a 1000 m sprint. It takes 4s to travel 10m. What is the instananeous speed at the 5m mark? acceleration is constant.
(5m mark is 10 m as they start at -5m)
X=Distance
U=initial speed (U= 0m/s)
Note. This is the first thing I've tried since joining year 11 so i am quite a novice and may have just made a stupid error


Homework Equations


X=ut+1/2at^2
V=U+at


The Attempt at a Solution


x=ut+1/2at^2
10=(1/2).(a).(16)
10=8.a
a=1.25

V=u+at
V=(1.25)(4)
V=5m/s

But the answers say it 3.5m/s.
 
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Your acceleration is correct and you used the equation correctly except for the second part. The time t=4s is for 10m displaced not for 5m. So, let's look at the given:

a = 1.25 m/s^2
Vo = 0
Vf = ?
displacement = 5m.

Note: You have three given, so you should be able to solve for Vf (instantaneous speed).
 
you are right
 
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