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Length Contraction causes Time Dilation? |
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| Mar29-11, 07:56 PM | #35 |
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Length Contraction causes Time Dilation?Frankly I am still not convinced you fully accepted the implications of special relativity. |
| Mar29-11, 09:16 PM | #36 |
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When you say "the universe contracting" what you are saying that certain objects in the universe are moving with respect to you and the distances between them are Lorentz contracted - according to you. Remember that according to one of those objects, you are the one who is moving and is Lorentz contracted. Similarly, the clocks on those objects appear to be ticking more slowly to you. But to them, your clock is ticking more slowly than theirs. The situation is symmetric, neither one is "right". |
| Mar30-11, 12:04 AM | #37 |
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If you crossed 640 light years fast enough that it was contracted down to 2 light years in your frame, while avoiding any time dilation strangely, and you then crossed THAT distance fast enough that you took just a little over 2 years to do so, wouldn't you then experience time dilation on THAT duration, and observe quite a bit less than 2 years during your trip? If the 2 light years in your frame was 640 light years for a signal laser you fired on the same trajectory when you left, then your trip would take more than the 640 years required for a detector at your destination to receive the signal. Yes, in your frame, you'd only experience/age/observe 2~ years, and claim your laser beam only crossed 2 light years. If you then turned around and fired a reply laser while going fast enough that you again measure the beam traveling for only 2 years as it crossed 2 light years, you would return 1280+ years after you left, roughly 4 years older. If the contraction observed from your frame meant you only took 2 years to cross that distance without any effects from time dilation, you'd arrive at Betelgeuse 638~ years before the signal laser, and you'd make it home a thousand years or so before you even left! |
| Mar30-11, 05:22 AM | #38 |
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The fact that you have only aged 4++ years while those on Earth have aged 1280++ years is called the twin "paradox". |
| Mar30-11, 06:00 AM | #39 |
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In addition:
Here you switched from using one inertial frame to another for one observer. For a reality-like description that is not allowed; in that sense, the class of inertial frames is preferred in special relativity. For "twin-paradox" scenarios in which one observer switches inertial frames (or in which he uses a non-inertial frame), only* the description of the other observer who does not switch frames provides a consistent and realistic explanation in SR (loosely said: "frame-hopping" leads to inconsistent or unreal descriptions). Cheers, Harald *Einstein tried to get rid of that with GR, but most people nowadays don't appreciate the reality of "induced gravitational fields". |
| Mar30-11, 09:23 AM | #40 |
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There are two events at the start of the thought experiment, we'll just assume the ship was flying past the Earth to confirm that it is not simply a confusion on my part due to an admitted preference for background star reference frames, and to take acceleration out of the equation entirely. The ship flies past the Earth at the spacetime event: (x+y+z=0, t=2011 CE), and fired a signal laser towards Betelgeuse, the ship synchronized their clocks as they passed by, so they're now tallying up information which they can perform a measurement with. A bored astronomer decides to tally up measurement as well, he records the ship hauling off along the x axis (for simplicity), with the laser inching further and further ahead of it. In the ships frame the Earth whizzed past at nearly the speed of light, and continued receding along the x axis, while the laser the ship fired races away at the speed of light towards Betelgeuse. There is another event of note here, Betelgeuse, located at (x=+640 light years from the Earth/Ship rendezvous point, t=3/30/2011 CE) along a spacelike trajectory oriented along the ships flight path. In the Earth frame it is just sitting there, 640 years away at the speed of light, picking it's red supergiant nose. In the ship frame it is hurtling towards the point where the Earth was when the ship passed it at nearly the speed of light. In 2 years, Earth frame, the astronomer notes that the beam of light has traveled 2 light years, the ship has traveled 1.9999999~ whatever light years, and that Betelgeuse flicked a massive coronal booger roughly in the direction of Rigel... but otherwise did nothing of interest. At the spacetime event (x=+2 light years from the Earth/Ship rendezvous point, t=3/30/2013 CE), the passenger on the ship checks his instruments and determines that he is at (x=+.011~ or so light years from the E/SrP, t=4/3/2011), a mere 3 days have passed since the Earth flew past him... for some reason, probably a sale at the interstellar mall... and he notes that since his signal laser can't be more than 3 light days ahead of him at this point, he inputs that measurement into his super parallax measuring doohickie and it tells him Betelgeuse is a bit more than 200 times as far away from him as his signal laser, so it must be just under 2 light years away! Is he correct? Well yeah, I guess, in a sense, as he has no reason to think he's actually in a frame experiencing major relativistic effects. He did measure the correct distances/duration as far as his frame is concerned. The question here is, is there any manner in which his completely real and accurate measurements can be reconciled with any frame besides his (besides the arbitrary selection of suitably chosen frames which someone would point out exist if I didn't mention them)? Is he doomed to watch the squished up universe hurtle past him, Unable to consider that perhaps he was in a boosted frame, and that just maybe his measurements were distorted by it? If there was no way for the guy in the ship to determine that he had been in motion, that would give the appearance of a paradox, and this often confuses people upon first hearing it. If you can't tell by now, my problem is being all too aware of how that "paradox" is resolved. The only way the passenger on the ship can claim the universe is contracted around him is if he can't break the symmetry between his frame and another observers frame. Setting aside the issue that he would remember accelerating, and putting him in the above described flyby scenario, then yes, he could claim that his frame was inertial and undistorted. It's a rather scary place, his choice of coordinates, what with stars and planets hurtling past at nearly the speed of light... I mean, yes, we're whirling around along several different axes at anything from a few hundred, to a several thousands, all the way up to a million or so miles an hour depending on which motion you want to consider... but that's pretty far from sitting there with gigantic balls of nuclear fire hurtling towards you at 670 million mph. /sigh Again, my issue is in no way related to an inability to understand an example I put forth in an effort to be understood, though the irony is rich enough that it could smother the heart of a massive star and cause it to supernova. Technically, the twin paradox ONLY arises if you neglect acceleration completely, ANY change in direction breaks the symmetry between the frames, resolving the apparent paradox to be nothing but a quirky result of the way spacetime rotations work. |
| Mar30-11, 10:02 AM | #41 |
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| Mar30-11, 10:56 AM | #42 |
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| Mar30-11, 11:58 AM | #43 |
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I know all about that, but there is a way for him to determine his frame is not symmetrical with all others, he accelerated.
The "true" motion of the stars doesn't require a mere assumption if you notice they all have a significant vector and velocity relative to you. At rest or not, it pushes the limits of realistic explanations, plus he would notice the blue shift/red shift and aberration of the CMBR... but those are all far above the level of this conversation. For the record, I first learned about relativity back in the mid 80's, and am well versed in not just the stripped down explanations of the theory as usually provided to laymen, but also the mathematical underpinnings, as well as the rich scientific principles upon which the whole theoretical structure was built almost a hundred years ago. Now, I was a little datasponge of a 6 year old Aspie, between the bookshelf full of various out of date encyclopedias (I still pull up random factoids from the old white cover 1963 Britannica at the strangest times, my favorites were the A's, M's, P's, and the S's!), and my precious books on Relativity (Black Holes and Warped Spacetime, and Einstein: the Life and Times)... so while it may sound a little improbable for someone to say they've been studying something like Relativity since they were a little kid... it isn't that odd if you've ever met a 6 year old with Asperger's Syndrome. If it wasn't the rock collection, dinosaur trivia, or Legos... I was talking your ear off about how awesome Wheeler and Kerr metrics were. |
| Mar30-11, 12:20 PM | #44 |
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You wrote: |
| Mar30-11, 01:14 PM | #45 |
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You observe a beam of light moving away from you at the speed of light, even if you're going .99999999999999999999~ c, it still races off at full speed, rather than gradually creeping ahead due to you ALMOST being at light speed yourself. If you're in a Ferrari 458 doing 198 mph side by side with a McLaren MP4-12c doing 200 mph, he's going to ever so slightly nudge out in front and continue crawling further and further ahead. If you're racing along at almost the speed of light, to an observer as you rush past, you're going to lag bit by bit behind a beam of light. Yet you see the beam zoom off like you were standing still... why? When you're moving faster through space, you're moving slower through time. What you register as being a second in which the beam of light gains nearly 300,000 kilometers on you is a much longer time for an observer who isn't scooting along quite so quickly as you are. Note that they don't have to be at rest, if you're doing .99999999999999999999995 c and I'm doing .99995 c, we'll each observe the other appearing to slow down, the clocks we're conveniently holding both seem to tick slower for the other guy, as we've all established repeatedly. Once we come to a stop though, my clock will have ticked more than yours, I'll have aged a bit quicker than you did, though we both hardly aged compared to someone waiting for us back at Earth. This is why you can't say "the distances contract, so you take less time to cross them", it's completely backwards. You experience less time because of your velocity, which causes you to claim everything else is contracted. http://www.phys.unsw.edu.au/einstein...ation.htm#true |
| Mar30-11, 01:23 PM | #46 |
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| Mar30-11, 02:07 PM | #47 |
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I never said he would notice any changes, his clock ticks off one second every time he expects it should, like... clockwork.
Another observer watching his clock tick from a slower moving frame would see it tick slower (and vice versa), but if the faster moving traveler came to rest beside the slower moving observer it would be obvious that the traveler's clock had ticked less. I actually was using velocity, and never said anything about absolute speed. If we were both at rest together in an inertial frame and pulled out two completely identical stopwatches, started them at exactly the same moment, then we both accelerated up to particular fraction of the speed of light, except you got much closer to c than I did, when we came to a stop afterwards your watch would read a shorter duration for your trip than mine would. Where is the confusion here? |
| Mar30-11, 02:42 PM | #48 |
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A lightlike path connecting Earth and Betelgeuse is 640 light years long in the Earth frame and takes 640 years to travel in the Earth frame. Distance and time are relative quantities, and like all relative quantities, you must identify the reference frame to which they refer. The following statements are also correct for your scenario. There exists some frame in which a lightlike path connecting Earth and Betelgeuse is 2 light years long and takes 2 years to travel. In a frame moving 0.999995 c wrt Earth in the direction from Earth to Betelgeuse the distance between Earth and Betelgeuse is 2 light years. In this frame it takes light 1.000002 years to go from Earth to Betelgeuse or 409599 years to go from Betelgeuse to Earth. In this frame it takes 2.00001 years from the time that Earth passes the origin for Betelgeuse to pass the origin. Notice how relative quantities are always referenced to some specific frame. You make other comments like "they are in a significantly dilated frame of reference" and "he's actually in a frame experiencing major relativistic effects" which lead me to believe that the omission I point out above is not simply a gaffe, but is a basic misunderstanding. |
| Mar30-11, 04:44 PM | #49 |
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See, here's the problem, you're saying the effects are real in that they do happen, I'm saying that as well, but that the cause is due to measurement from a particular frame, not the universe actually smushing up around you.
I do admit that I'm a bit overly insistent about the broken symmetry, but the length required to treat someone flying from here to another star as an intertial frame leaves a bad taste in my mouth. I know his frame is accelerated, he knows his frame is accelerated, thinking about the hypothetical inertial frame is one thing, but it is another to claim the particular details of measurement within said hypothetical inertial frame are the cause of the effects you experience in an accelerated frame. At that point it isn't just a matter of "earth and betelgeuse went flying past me", unless you're pretending GR doesn't exist, and topping it off by pretending that you can't handle acceleration at all in SR (you can, it just doesn't do it very easily). |
| Mar30-11, 05:49 PM | #50 |
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| Mar30-11, 06:59 PM | #51 |
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