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#19
Feb1212, 02:50 AM

P: 633

Remember what the question is: Find the possible slopes. The equation of line in #12 is in terms of the slope (represented by m). Your next step should be to obtain x and y intercepts in terms of this slope m. 


#20
Feb1212, 03:47 AM

P: 127

[itex]y_{intercept}[/itex] y=34m Is this correct? Whats the next step? 


#21
Feb1212, 12:41 PM

P: 633

Almost there!
You figured out the next step in #16, as quoted below: 


#22
Feb1212, 01:56 PM

P: 127

[itex]y=34m[/itex]
[itex]0=mx+34m[/itex] [itex]mx=34m[/itex] (dividing by m) [itex]x=\frac{3}{m}+4[/itex] [itex]xy=54[/itex], then [itex](\frac{3}{m}+4)(34m)=54[/itex] [itex]\frac{9}{m}+4m*\frac{3}{m}+1216m=54[/itex] [itex]\frac{9}{m}16m=30[/itex] (multiplying by m, we get a quadratic) [itex]16m^{2}+30+9=0[/itex] With the roots 3/2 and 3/8 Awesomenessness ... Thank you very much your patience :) 


#23
Feb1212, 02:07 PM

P: 633

Right. Now multiply both sides by m. You will arrive at an equation quadratic in m. Solving this will give you the possible values of slope.
As a verification, you should check if the sign of the solutions is negative, as SammyS suggested. 


#24
Feb1212, 02:29 PM

P: 127

Yes ... Solved ... Thank's again :)



#25
Feb1212, 02:47 PM

P: 633

No problem



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