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Integral calculus: plane areas in rectangular coordinates 
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#1
Feb2812, 07:21 AM

P: 20

1. The problem statement, all variables and given/known data
Find the area between y= 1/(x^{2}+1) and the xaxis, from x=0 to x=1 3. The attempt at a solution so when x=0, y=1 and when x=1, y=1/2 next i plot the points, so the intersection of the given equation is (0,1) and (1,1/2) Yh= Yhigher= 1/(x^{2}+1) Yl= Ylower= 0 the strip is vertical, so the length (L) = (YhYl) and the width (W) is dx dA=LW dA=(YhYl)dx dA=(1/(x^{2}+1))dx A=∫from 01 dx/(x^{2}+1) A=Arctan x from 01 A=Arctan 1 Arctan 0 A=pi/4 sq.units was my solution correct? 


#2
Feb2812, 09:53 AM

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P: 3,307

looks good to me



#3
Feb2812, 09:58 AM

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P: 7,819

You went through a lot of steps to get the answer. 


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