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Thermodynamics: Internal Energy and Enthalpy |
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| Apr24-12, 12:28 AM | #1 |
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Thermodynamics: Internal Energy and Enthalpy
H = U+ pV
pV = nRT H= U+ nRT H= H (T) I dont understand the transition from U+ nRT to H (T) Can someone explain this? I get that H = U + pV But how is H= U+ nR |
| Apr24-12, 02:14 AM | #2 |
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For a monoatomic ideal gas, U=(3/2) PV. Hence, H=(5/2) PV=(5/2) nRT
Which shows that H for an ideal gas is a function of T alone ,i.e, H=H(T). Of course it is also function of n since it is extensive quantity. However, this dependence is easy to get rid of by defining h=H/n which is an intensive quantity. |
| Apr24-12, 10:12 PM | #3 |
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thank you...that clears it up!
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