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Gravity working on BH |
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| Sep8-12, 09:04 PM | #1 |
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Gravity working on BH
Hi.
BHs receive gravity of other stars and then move. Does this mean that information of gravity of other stars go beyond event horizon around BHs to let them move? Thanks for your teachings in advance. |
| Sep8-12, 09:23 PM | #2 |
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Yes. An event horizon is like a one-way membrane. It lets information in, but not out.
Although you didn't ask about it, we could also ask about the transmission of information in the opposite direction by the same mechanism. The black hole does make gravitational forces on other stars. But this isn't really what we mean by transmission of information out through the event horizon. What we mean by that is really that a particle's world-line escapes -- and that's what doesn't happen. |
| Sep9-12, 08:25 AM | #3 |
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Thanks.
Signal of gravity from other stars lose speed approaching the event horizon thus does not it take infinite time to go through the event horizon ? |
| Sep9-12, 08:51 AM | #4 |
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Mentor
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Gravity working on BHI suspect you are thinking of a coordinate dependent effect of the Schwarzschild coordinates. |
| Sep9-12, 10:44 AM | #5 |
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| Sep9-12, 11:25 AM | #6 |
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| Sep9-12, 07:03 PM | #7 |
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I read sweet springs question to be this:
If two stars are on opposite sides of a BH, is the BH "absorbing" or "blocking" the gravitational influence of one star's "gravitational message" to the other star? Sometimes the distance "line of sight" between two object on each side of a BH is characterized as being infinite. |
| Sep9-12, 10:56 PM | #8 |
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If we imagine a binary BH system orbiting a barycenter wouldn't the orbits require constant exchange of information or waves,gravitons or something that updated the geometry relative to their changing locations? Or is such a system impossible in principle because of the barrier imposed by the horizon?? |
| Sep10-12, 07:31 AM | #9 |
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Hi.
There is a system composed of a star and a BH. The BH moves receiving gravity originated from the star. May I understand right that the BH does not move for a distant observer because gravity caused by the star cannot enter into the even horizon in finite time ? Regards. |
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