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Which is greater?

by lalapnt
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piercebeatz
#19
Nov14-12, 07:31 PM
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Quote Quote by Mark44 View Post
I doubt that any instructor would accept a proof in which most of the symbols are ?.
You could make it an equation and use the same method... i.e. let root(13)-root(12)+x=root(12)-root(11). If x>0, then the left side is greater. If x<0, the right side is greater
micromass
#20
Nov14-12, 08:22 PM
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Quote Quote by piercebeatz View Post
You could make it an equation and use the same method... i.e. let root(13)-root(12)+x=root(12)-root(11). If x>0, then the left side is greater. If x<0, the right side is greater
If the left side is greater, then you can't write an = between the sides.

Am I understanding you wrong?
piercebeatz
#21
Nov14-12, 08:51 PM
P: 242
Quote Quote by micromass View Post
If the left side is greater, then you can't write an = between the sides.

Am I understanding you wrong?
let x be the difference between the two. if, in the above scenario, x>0, then the left side must be less than the right, and vice versa.
Mark44
#22
Nov15-12, 12:20 AM
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Quote Quote by piercebeatz View Post
You could make it an equation and use the same method... i.e. let root(13)-root(12)+x=root(12)-root(11). If x>0, then the left side is greater. If x<0, the right side is greater
And then the problem becomes determining the sign of x.
tahayassen
#23
Nov15-12, 07:57 PM
P: 273
Quote Quote by Mark44 View Post
And then the problem becomes determining the sign of x.
Why's that?

Edit: Never-mind. I see why. It's because you square both sides, so when you solve for x, you get |x|=some number.

I would go with Bipolarity's method if you need a proof.


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