- #1
lalapnt
- 17
- 0
how do i work this out?
I like this approach. You can see at a glance which difference is larger.tahayassen said:Think of the square root function graphed.
tahayassen said:Think of the square root function graphed.
arildno said:Remember that for any two numbers, a and b, we have: (a-b)*(a+b)=a^2-b^2
i don't want to solve this graphically. (not like i even know how. I need some help here)tahayassen said:Think of the square root function graphed.
Are you saying you don't know what the graph of y = ##\sqrt{x}## looks like?lalapnt said:i don't want to solve this graphically. (not like i even know how. I need some help here)
Mark44 said:Are you saying you don't know what the graph of y = ##\sqrt{x}## looks like?
The graph of y = √x is one of the first ones you learn when you learn to graph functions. If you are asking questions about square roots, it's one you should know.lalapnt said:oh no! i know that! but first, i don't want to solve this graphically even if i did, how does the graph of y = √x help out?
EDIT: if i knew everything in math, i wouldn't be here.
Mark44 said:The graph of y = √x is one of the first ones you learn when you learn to graph functions. If you are asking questions about square roots, it's one you should know.
Look at the graph of this function. Does the y value on the graph change more between 11 and 12 than it does between 12 and 13, or does it change less between 11 and 12 than it does between 12 and 13?
but how is 2sqrt(12) = 48? :/dextercioby said:Purely algebra ?
Place ? i/o =, > or <.
sqrt(12)-sqrt(11) ? sqrt(13)-sqrt(12)
2sqrt(12) ? sqrt(11)+sqrt(13)
48 ? ...
Can you continue ?
Mark44 said:I doubt that any instructor would accept a proof in which most of the symbols are ?.
piercebeatz said:You could make it an equation and use the same method... i.e. let root(13)-root(12)+x=root(12)-root(11). If x>0, then the left side is greater. If x<0, the right side is greater
micromass said:If the left side is greater, then you can't write an = between the sides.
Am I understanding you wrong?
And then the problem becomes determining the sign of x.piercebeatz said:You could make it an equation and use the same method... i.e. let root(13)-root(12)+x=root(12)-root(11). If x>0, then the left side is greater. If x<0, the right side is greater
Mark44 said:And then the problem becomes determining the sign of x.
Work and power are two related but distinct concepts in physics. Work is defined as the amount of force applied to an object multiplied by the distance the object moves in the direction of the force. Power, on the other hand, is the rate at which work is done or energy is transferred.
Work is calculated by multiplying the force applied to an object by the distance the object moves in the direction of the force. The equation for work is W = Fd, where W is work, F is force, and d is distance.
Power is related to work through the equation P = W/t, where P is power, W is work, and t is time. This equation shows that power is the amount of work done per unit of time.
This question cannot be answered definitively as it depends on the specific situation. In some cases, work may be greater than power if a large amount of force is applied over a long distance, resulting in a high amount of work being done. In other cases, power may be greater than work if a smaller amount of force is applied over a shorter distance, but at a faster rate.
Work and power are both related to energy, as they are both measures of the transfer of energy. Work is the transfer of energy from one object to another, while power is the rate at which energy is transferred. In other words, work and power are both ways of measuring energy in motion.