- #1
jeckel7234
- 4
- 0
given
∫(2-5) f(x)dx=5 and ∫(4-5) f(x)dx=∏ , find
a)
∫(5-5) f(x)dx =
b)
∫(5-4) f(x)dx =
c)
∫(2-4 f(x)dx =
Im going over old tests of mine to get ready for my final, and I can't find anywhere in my notes how I solved this, I originally got (a. 0 b. ∏ c. 5-∏). Can someone just explain the process of how to solve this. I understand b) by changing the sign and swapping the limits equals one of the given integrals, I just can't understand how I got A and C?
Thanks and Hi everyone
∫(2-5) f(x)dx=5 and ∫(4-5) f(x)dx=∏ , find
a)
∫(5-5) f(x)dx =
b)
∫(5-4) f(x)dx =
c)
∫(2-4 f(x)dx =
Im going over old tests of mine to get ready for my final, and I can't find anywhere in my notes how I solved this, I originally got (a. 0 b. ∏ c. 5-∏). Can someone just explain the process of how to solve this. I understand b) by changing the sign and swapping the limits equals one of the given integrals, I just can't understand how I got A and C?
Thanks and Hi everyone