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do all quarks get annihilated? |
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| Dec13-12, 05:32 AM | #1 |
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do all quarks get annihilated?
Im aware of quark antiquark annihilation in a proton and have heard one opinon but want another. Do all the quarks get annihilated and just the number remain 3 remain constant in the proton or are the 2 up and 1 down quark the specific quarks that exist in the middle of the storm and they never go? how long do we think it takes for a full quark turnover?
is this also proved or just theory? |
| Dec13-12, 06:24 AM | #2 |
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There are no specific quarks inside a proton that would be "untouchable": no quark is protected. Every single quark can be annihilated any time and other quarks are created in the meantime. There is just a small abundance of 2 up quarks above anti-up, and there is 1 more down on top of all anti-down. But again - the extra quarks are not special. You cannot say if a particular up is the extra one or not. All quarks are subject of the annihilation / creation. Please also note that it is much more complicated. It's a messy inferno that cannot be easily described. It's impossible to even find out how many quarks there are inside a proton, because the number is changing extremely fast and actually it is uncertain. There are not only up and down quarks and antiquarks, but also strange quarks, gluons, etc., all of them moving at relativistic speeds, colliding, scattering, annihilating. |
| Dec13-12, 06:52 AM | #3 |
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| Dec13-12, 07:37 AM | #4 |
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Mentor
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do all quarks get annihilated?
There are no proofs in physics, but the quark model is extremely successful, and there is no similar alternative.
"Proton" is just a word for this mess of quarks and gluons. |
| Dec13-12, 04:54 PM | #5 |
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In fact the proton is a time-independent state. Its quark/gluon content does not change with time, let alone seethe. Rather the number of quarks and gluons present in a proton has a certain probability distribution. |
| Dec13-12, 05:47 PM | #6 |
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Recognitions:
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It's hardly worth making a distinction. Time evolution of a proton is just a sum over all possible diagrams. In each particular diagram, there is quite a bit of "seething" going on. The sum over all possibilities gives you a steady state. It's not wrong to say that there are constant creation-annihilation processes going on within the proton. There are. They simply happen to be balanced to give you a particular state.
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| Dec14-12, 09:55 AM | #7 |
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One can tell from the followup questions we get how misleading things like this can be. We hear: charged particles shooting photons at each other. Angular momentum vectors wobbling back and forth, electrons dancing around the nucleus in well-defined orbits. Does Schrodinger's Cat "change extremely fast" between being alive and dead? Descriptions like these lead the novice to plausibly ask how fast, how often, what happens in between, and so on. Explaining them as simply examples of quantum superposition avoids the confusion. The confusion extends, I'm afraid, to physics graduate students, who from taking a course in field theory get the impression that "diagrams" are the universal answer, and that time-dependent perturbation theory is appropriate for everything, including bound states. Or that the structure of protons can be understood from any kind of perturbation theory at all. |
| Dec14-12, 10:46 AM | #8 |
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Recognitions:
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You can do non-perturbative QCD with diagrams. You just need infinitely many of them. :p That's, by the way, the only way I know how to actually do computations of proton structure. Approximations are made, and corners are cut, but it's not bad, all things considered.
But more importantly, we shouldn't be tailoring our jargon for the laymen. Scientists and medical doctors used to speak Latin specifically to exclude the laymen. Now, the fields have gotten complex enough for it not to be strictly necessary. (Though, I think we should have stuck with it.) It's very important to be able to quickly distinguish between scientists and people who try to pretend to be scientists. When a student doing field theory asks about photon exchange in a scattering process, I can immediately tell a difference from someone who has no idea what they are talking about. In the later case, I'm going to try and lead the discussion towards a classical case, if it is possible. There is absolutely no reason to try and explain details of how QFT works to a person who doesn't know anything about QFT. OP has been asking questions which amount to asking if we can pin-point a specific quark in a proton. Answer is no. And I have no better means of explaining it than saying that quarks are constantly created and destroyed. You think you can explain the full case, where number of quarks is a distribution to this person? You give it a shot. |
| Dec14-12, 02:54 PM | #9 |
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A good way to deal with this kind of thing is to write a FAQ. We have FAQ sections in relativity and cosmology. It would be good to start building one for this subforum. |
| Dec15-12, 09:45 AM | #10 |
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| Dec15-12, 10:05 AM | #11 |
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Mentor
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Simple: The kinetic energy is the same all the time.
You always have a superposition of many particles with different kinetic energy, and if you sum over all of those particles you get a constant value. |
| Dec15-12, 12:44 PM | #12 |
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| Dec16-12, 04:46 PM | #13 |
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| Dec17-12, 10:19 AM | #14 |
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