- #1
sahil_time
- 108
- 0
We know that we calculate the volume of sphere by taking infinitesimally small cylinders.
∫ ∏x^2dh
Limits are from R→0
x is the radius of any randomly chosen circle
dh is the height of the cylindrical volume.
x^2 + h^2 = R^2
So we will get 4/3∏R^3
Now the question is why cannot we obtain the SURFACE AREA using, infinitesimally small cylinders. Where
∫ 2∏xdh
Limits are from R→0
x is the radius of any randomly chosen circle
dh is the height of the cylindrical volume.
x^2 + h^2 = R^2.
I have a certain explanation for this which works well, but i would like to know if there is an unambiguous answer.
Thankyou :)
∫ ∏x^2dh
Limits are from R→0
x is the radius of any randomly chosen circle
dh is the height of the cylindrical volume.
x^2 + h^2 = R^2
So we will get 4/3∏R^3
Now the question is why cannot we obtain the SURFACE AREA using, infinitesimally small cylinders. Where
∫ 2∏xdh
Limits are from R→0
x is the radius of any randomly chosen circle
dh is the height of the cylindrical volume.
x^2 + h^2 = R^2.
I have a certain explanation for this which works well, but i would like to know if there is an unambiguous answer.
Thankyou :)