# The Rock and the Window

by mgerman63016
Tags: rock, window
 P: 12 1. A rock is dropped off the top of a building. On the way down, the rock passes a window. The window is known to be tall and the stone takes 0.154 to fall past the window. 1. What is the velocity of the rock at the bottom of the window? 2. How much time was necessary from the instant the rock was dropped until it reached the top of the window? 3. How far above the top of the window was the rock dropped? So far I got Yi=2.00m Vi=? a=9.81m/s^2 t= 0.154s Yf= 0m Vf=0m/s I also got the initial velocity for the top window to be 12.98m/s which because I got my estimation wrong I got the answer wrong...sigh...BUT if I can get a little guidance I would GREATLY appreciate it! THANKS And for my equation I used V = Δx/Δt = 2.00/0.154 = 12.98 m/s
 PF Patron Thanks P: 4,500 The equation you used is good for an unaccelerated motion. The rock's is accelerated. What equations should you use for it?
 P: 12 could i use the 2a(y-yi)=Vy2-Voy2??
PF Patron
Thanks
P: 4,500

## The Rock and the Window

This equation alone will not do it. What is the basic equation of uniformly accelerated motion?

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