Register to reply

The Rock and the Window

by mgerman63016
Tags: rock, window
Share this thread:
mgerman63016
#1
Jan28-13, 12:34 AM
P: 12
1. A rock is dropped off the top of a building. On the way down, the rock passes a window. The window is known to be tall and the stone takes 0.154 to fall past the window.

1. What is the velocity of the rock at the bottom of the window?
2. How much time was necessary from the instant the rock was dropped until it reached the top of the window?
3. How far above the top of the window was the rock dropped?


So far I got
Yi=2.00m
Vi=?
a=9.81m/s^2
t= 0.154s
Yf= 0m
Vf=0m/s



I also got the initial velocity for the top window to be 12.98m/s which because I got my estimation wrong I got the answer wrong...sigh...BUT if I can get a little guidance I would GREATLY appreciate it! THANKS

And for my equation I used V = Δx/Δt = 2.00/0.154 = 12.98 m/s
Phys.Org News Partner Science news on Phys.org
New model helps explain how provisions promote or reduce wildlife disease
Stress can make hard-working mongooses less likely to help in the future
Grammatical habits in written English reveal linguistic features of non-native speakers' languages
voko
#2
Jan28-13, 03:30 AM
Thanks
P: 5,663
The equation you used is good for an unaccelerated motion. The rock's is accelerated. What equations should you use for it?
mgerman63016
#3
Jan28-13, 12:37 PM
P: 12
could i use the

2a(y-yi)=Vy2-Voy2??

voko
#4
Jan28-13, 12:53 PM
Thanks
P: 5,663
The Rock and the Window

This equation alone will not do it. What is the basic equation of uniformly accelerated motion?


Register to reply

Related Discussions
Rock and Window Introductory Physics Homework 3
Force on an airplane window, given altitude and area of the window. Introductory Physics Homework 2
Window material General Engineering 8
Window washer Introductory Physics Homework 1
Fan by the Window Introductory Physics Homework 3