A probability question based on batting averages, need help


by shadedude123
Tags: average, batting, probabilities, probability
shadedude123
shadedude123 is offline
#1
Feb20-13, 06:16 PM
P: 10
Batter A has a batting average (probability of getting a hit) of .320. Batter B has a
batting average of .280. If both of them come to bat during an inning, calculate the
probability that neither one gets a hit. Assume that A getting a hit is independent of B
getting a hit.

My attempt:

I said that .320 is basically 320/1000 and that's 8/25 and .280 is 7/25. I said that the probability of them not getting a hit is 17/25 for Batter A and 18/25 for batter B. And I multiplied both of em to get 48.96% chance of both of em missing. Is this right? I'm not really a math type person but this question is for one of my science classes. Thanks for any help :)
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ImaLooser
ImaLooser is offline
#2
Feb21-13, 12:05 AM
P: 571
Quote Quote by shadedude123 View Post
Batter A has a batting average (probability of getting a hit) of .320. Batter B has a
batting average of .280. If both of them come to bat during an inning, calculate the
probability that neither one gets a hit. Assume that A getting a hit is independent of B
getting a hit.

My attempt:

I said that .320 is basically 320/1000 and that's 8/25 and .280 is 7/25. I said that the probability of them not getting a hit is 17/25 for Batter A and 18/25 for batter B. And I multiplied both of em to get 48.96% chance of both of em missing. Is this right? I'm not really a math type person but this question is for one of my science classes. Thanks for any help :)
100% correct.
shadedude123
shadedude123 is offline
#3
Feb21-13, 07:08 AM
P: 10
Thanks a lot :)


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