## A probability question based on batting averages, need help

Batter A has a batting average (probability of getting a hit) of .320. Batter B has a
batting average of .280. If both of them come to bat during an inning, calculate the
probability that neither one gets a hit. Assume that A getting a hit is independent of B
getting a hit.

My attempt:

I said that .320 is basically 320/1000 and that's 8/25 and .280 is 7/25. I said that the probability of them not getting a hit is 17/25 for Batter A and 18/25 for batter B. And I multiplied both of em to get 48.96% chance of both of em missing. Is this right? I'm not really a math type person but this question is for one of my science classes. Thanks for any help :)

 Quote by shadedude123 Batter A has a batting average (probability of getting a hit) of .320. Batter B has a batting average of .280. If both of them come to bat during an inning, calculate the probability that neither one gets a hit. Assume that A getting a hit is independent of B getting a hit. My attempt: I said that .320 is basically 320/1000 and that's 8/25 and .280 is 7/25. I said that the probability of them not getting a hit is 17/25 for Batter A and 18/25 for batter B. And I multiplied both of em to get 48.96% chance of both of em missing. Is this right? I'm not really a math type person but this question is for one of my science classes. Thanks for any help :)
100% correct.
 Thanks a lot :)

 Tags average, batting, probabilities, probability