Dot Product: Understand When to Use Each Method

  • Thread starter Thread starter mindheavy
  • Start date Start date
  • Tags Tags
    Dot Vector
AI Thread Summary
The discussion clarifies the use of two methods for calculating the dot product of vectors. The first method, u·v = u_i·v_i + u_j·v_j, is applicable when the components of the vectors are known, allowing for straightforward calculation. The second method, u·v = |u|·|v|cosθ, is used when the magnitudes of the vectors and the angle between them are provided. It emphasizes that the choice of method depends on the available information and the desired outcome. Understanding these contexts aids in effectively applying the dot product in various scenarios.
mindheavy
Messages
62
Reaction score
0
I'm reading up on dot products and keep seeing two different examples.

One states that u\cdotv = u_{i}\cdotv_{i} + u_{j}\cdotv_{j}

Another: u\cdotv = |u|\cdot|v|cosθ

I'm not understanding when to use the first or second method?
 
Mathematics news on Phys.org
mindheavy said:
I'm reading up on dot products and keep seeing two different examples.

One states that u\cdotv = u_{i}\cdotv_{i} + u_{j}\cdotv_{j}

Another: u\cdotv = |u|\cdot|v|cosθ

I'm not understanding when to use the first or second method?
At the risk of stating something obvious, it depends on what information you are given and what you are trying to find. If you know the two vectors then you can find the dot product using the first equation. Then you can find the angle between the vectors using the second equation.

On the other hand, if you are given the lengths of the vectors and the angle between them, you can use the second equation to find the dot product.
 
Makes sense, I think the way the book I'm looking in words it was confusing me. Thanks
 
For example, if you are given that one vector is <1, 0, 0> and the other is <2, 2, 0> it is easy to calculate that the dot product is 1(2)+ 0(2)+ 0(0)= 2.

But if you are given that one angle has length 1, the other has length 2\sqrt{2}, and the angle between them is \pi/4, it is easiest to calculate (1)(2\sqrt{2})(cos(\pi&#039;4)= 2.

By the way, in spaces of dimension higher than 3, we can use the "sum of products of corresponding components" to find the dot product between two vectors, then use |u||v|cos(\theta) to define the "angle between to vectors".
 
Thread 'Video on imaginary numbers and some queries'
Hi, I was watching the following video. I found some points confusing. Could you please help me to understand the gaps? Thanks, in advance! Question 1: Around 4:22, the video says the following. So for those mathematicians, negative numbers didn't exist. You could subtract, that is find the difference between two positive quantities, but you couldn't have a negative answer or negative coefficients. Mathematicians were so averse to negative numbers that there was no single quadratic...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...

Similar threads

Replies
4
Views
3K
Replies
4
Views
3K
Replies
5
Views
2K
Replies
33
Views
4K
Replies
8
Views
2K
Replies
5
Views
2K
Replies
10
Views
3K
Back
Top