What makes SiO2 an excellent cladding material for optical fibers?

AI Thread Summary
SiO2, or silicon dioxide, is recognized as an excellent cladding material for optical fibers due to its low refractive index, which enhances light transmission. Unlike germanium oxide, SiO2 is not water-soluble, making it more stable and durable for fiber applications. Its properties contribute to efficient light guiding and minimal signal loss in optical fibers. The discussion emphasizes the importance of SiO2's characteristics in fiber optics technology. Understanding these properties is crucial for advancements in optical communication systems.
Ghassan99
Messages
17
Reaction score
0
can anyone please explain this property of silicon:
An excellent oxide as the low-refractive-index cladding material.
thanks
 
Engineering news on Phys.org
That wouldn't be a property of silicon but presumably it's native oxide, SiO2. It's an excellent oxide because it isn't water soluble as germanium oxide (GeO2).

SiO2's low refractive index means it is used to build optical fibers. You can find out a lot about this on Wikipedia.
 
While I was rolling out a shielded cable, a though came to my mind - what happens to the current flow in the cable if there came a short between the wire and the shield in both ends of the cable? For simplicity, lets assume a 1-wire copper wire wrapped in an aluminum shield. The wire and the shield has the same cross section area. There are insulating material between them, and in both ends there is a short between them. My first thought, the total resistance of the cable would be reduced...
Hi all I have some confusion about piezoelectrical sensors combination. If i have three acoustic piezoelectrical sensors (with same receive sensitivity in dB ref V/1uPa) placed at specific distance, these sensors receive acoustic signal from a sound source placed at far field distance (Plane Wave) and from broadside. I receive output of these sensors through individual preamplifiers, add them through hardware like summer circuit adder or in software after digitization and in this way got an...
I am not an electrical engineering student, but a lowly apprentice electrician. I learn both on the job and also take classes for my apprenticeship. I recently wired my first transformer and I understand that the neutral and ground are bonded together in the transformer or in the service. What I don't understand is, if the neutral is a current carrying conductor, which is then bonded to the ground conductor, why does current only flow back to its source and not on the ground path...
Back
Top