Uniform Circular Motion Question (Mechanics/Physics I)

AI Thread Summary
The discussion centers on a physics problem involving a car making a circular turn, with specific focus on calculating average acceleration. The car travels an arc length of 200 m in 34 seconds, and while parts A and B have been solved correctly, part C is proving challenging. The average acceleration formula a_avg = Δv/Δt is acknowledged, but the correct approach requires considering the vector nature of velocity changes in both x and y components. Participants emphasize the importance of calculating the changes in velocity vectorially, particularly for uniform circular motion. The conversation highlights the need for clarity in distinguishing between scalar and vector quantities in the calculations.
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Uniform Circular Motion Question Please Help! (Mechanics/Physics I)

A car initially traveling eastward turns north by traveling in a circular path at uniform speed as in Figure P6.10. The length of the arc ABC is 200 m, and the car completes the turn in 34.0 s.

(figure attached as "visual.gif")

Figure P6.10
(a) What is the acceleration when the car is at B located at an angle of 35.0°? Express your answer in terms of the unit vectors i and j.
(b) Determine the car's average speed.
(c) Determine its average acceleration during the 34.0 s and express your answer in terms of the unit vectors i and j.


I have properly solved Parts A and B. It is only Part C that I am having trouble with.

Relevant equation is probably just a avg = Δv/Δt

The Attempt at a Solution



Part A: -.2224i m/s^2 + .1558j m/s^2(This is correct)
Part B: 5.88 m/s (This is correct)

Part C: I have tried the following:

a avg = Δv/Δt, and Δv = ((5.88)^2 + (5.88)^2)^1/2 = 8.3189 m/s ==> a avg = (8.3189/34.0 s) = .2447 m/s^2 (not correct)

and

a avg = Δv/Δt, and Δv=(r/t) since it is circular motion and over 34 seconds the change in both x and y are equal to the radius. So Δv= (127.3240 m / 34.0 s) = 3.7448 m/s ==> a avg = Δv/Δt, so a avg = (3.7448 m/s / 34.0 s) = .1101 m/s^2 for both i and j (not correct).

I know I am overlooking something really simple here. I also realize that the signs will be different for i and j, just as they were in part A. Please help! :)
 

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Express ax and ay accelerations in terms of polar coordinates R and θ.

Then, average x accel = ax = ∫axdt/∫dt
and same for average y accel ay.

Then avg accel = a = ax i + ay j.
 
adamwest said:
a avg = Δv/Δt, and Δv = ((5.88)^2 + (5.88)^2)^1/2
As rude man points out, the acceleration should be a vector. Your a avg = Δv/Δt is correct, but Δv is a vector.
Δv=(r/t) since it is circular motion and over 34 seconds the change in both x and y are equal to the radius.
Good observation, but think about the x and y components of Δv. I.e. the change in vx and the change in vy.
 
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