Register to reply

De broglie waves

by asdf1
Tags: broglie, waves
Share this thread:
asdf1
#1
Oct28-05, 09:20 AM
P: 736
for the following question:
a hydorgen atom is 5.3*10^(-11) m in radius. use the uncertainty principle to estimate the minimum energy an electron acan have in this atom.

my problem:
to calculate the kinetic energy, do you use Ek=(p^2)/2m or Ek=pc????
Phys.Org News Partner Science news on Phys.org
'Office life' of bacteria may be their weak spot
Lunar explorers will walk at higher speeds than thought
Philips introduces BlueTouch, PulseRelief control for pain relief
El Hombre Invisible
#2
Oct28-05, 09:32 AM
P: 1,017
The uncertainty principal is: /\x/\p = h/2*pi.

/\x is the radius you have stated.

/\p is the uncertainty of momentum. p = mv, mass is known, so /\p = m/\v.

So: /\v = h/(2 * pi * m * /\x)

where m is the mass of the electron.

Find /\v, then you can find the minimum energy:

energy = 0.5 * m * /\v^2.
asdf1
#3
Oct29-05, 05:04 AM
P: 736
is that the same as just calculating the kinetic energy=p^2/2m?

El Hombre Invisible
#4
Oct29-05, 06:03 AM
P: 1,017
De broglie waves

Yep, that's another way.
asdf1
#5
Oct31-05, 08:00 AM
P: 736
ok~ that's cool!


Register to reply

Related Discussions
De-Broglie waves Introductory Physics Homework 4
De Broglie waves Introductory Physics Homework 4
De Broglie waves. Quantum Physics 1
De Broglie Waves Quantum Physics 13
De Broglie Waves Introductory Physics Homework 1