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De broglie waves

by asdf1
Tags: broglie, waves
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asdf1
#1
Oct28-05, 09:20 AM
P: 738
for the following question:
a hydorgen atom is 5.3*10^(-11) m in radius. use the uncertainty principle to estimate the minimum energy an electron acan have in this atom.

my problem:
to calculate the kinetic energy, do you use Ek=(p^2)/2m or Ek=pc????
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El Hombre Invisible
#2
Oct28-05, 09:32 AM
P: 1,017
The uncertainty principal is: /\x/\p = h/2*pi.

/\x is the radius you have stated.

/\p is the uncertainty of momentum. p = mv, mass is known, so /\p = m/\v.

So: /\v = h/(2 * pi * m * /\x)

where m is the mass of the electron.

Find /\v, then you can find the minimum energy:

energy = 0.5 * m * /\v^2.
asdf1
#3
Oct29-05, 05:04 AM
P: 738
is that the same as just calculating the kinetic energy=p^2/2m?

El Hombre Invisible
#4
Oct29-05, 06:03 AM
P: 1,017
De broglie waves

Yep, that's another way.
asdf1
#5
Oct31-05, 08:00 AM
P: 738
ok~ that's cool!


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