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de broglie waves |
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| Oct28-05, 09:20 AM | #1 |
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de broglie waves
for the following question:
a hydorgen atom is 5.3*10^(-11) m in radius. use the uncertainty principle to estimate the minimum energy an electron acan have in this atom. my problem: to calculate the kinetic energy, do you use Ek=(p^2)/2m or Ek=pc???? |
| Oct28-05, 09:32 AM | #2 |
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The uncertainty principal is: /\x/\p = h/2*pi.
/\x is the radius you have stated. /\p is the uncertainty of momentum. p = mv, mass is known, so /\p = m/\v. So: /\v = h/(2 * pi * m * /\x) where m is the mass of the electron. Find /\v, then you can find the minimum energy: energy = 0.5 * m * /\v^2. |
| Oct29-05, 05:04 AM | #3 |
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is that the same as just calculating the kinetic energy=p^2/2m?
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| Oct29-05, 06:03 AM | #4 |
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de broglie waves
Yep, that's another way.
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| Oct31-05, 08:00 AM | #5 |
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ok~ that's cool!
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