- #1
Edwin
- 162
- 0
How would you solve the following system of simultaneous equations for t and b?
sin(pi*t) = 0
sin(pi*(t^2 + 35)/(2*t)) = 0
(t^2 + 35)/(2*t) - t/2 - b/2 = 0
t^2/35 +35/t^2 -t/b - b/t = 0
t*b = 35
inquisitively,
Edwin G. Schasteen
sin(pi*t) = 0
sin(pi*(t^2 + 35)/(2*t)) = 0
(t^2 + 35)/(2*t) - t/2 - b/2 = 0
t^2/35 +35/t^2 -t/b - b/t = 0
t*b = 35
inquisitively,
Edwin G. Schasteen