malta said:Homework Statement
If the coefficient os static friction between the incline and block is .3, then what is the minimum force,F, needed to prevent the block from sliding?
m=20kg theta= 50 degrees
Homework Equations
Normal force= mgcosx
Fs= uk mgcosx
The Attempt at a Solution
I know how to solve this this for the perpendicular force (up the ramp) but I can't seem to figure out how to do it for thr parallel force.
malta said:Fore due to gravity is mgsinx and the frictional force = (coefficient of fiction)(mgCosx)
And the condition on all forces along the plane so that the block doesn't move has to equal to zero
But I can't seem to get what to set equal to what
malta said:ok so
F + mgcosx= N
(friction)N= mgSinx
So F = (mgSinx)/(friction) - mgCosx
There we go, thanks again
Static friction is a type of force that prevents an object from moving when a force is applied to it. It is the resistance between two surfaces that are not moving relative to each other.
When a block is placed on a surface, there is a force of gravity acting on it, trying to make it slide down. However, the atoms on the surface of the block and the surface it is resting on create a force called static friction, which acts in the opposite direction and prevents the block from sliding.
The strength of static friction depends on the nature of the surfaces in contact and the normal force exerted on the object. Rougher surfaces and a higher normal force will result in a higher static friction force.
If the force applied to the block is greater than the maximum static friction force, the block will overcome the static friction and start to slide. This is known as the point of static friction being exceeded.
No, the maximum static friction force can never be larger than the force applied. If an external force is applied that is greater than the maximum static friction force, the object will start to move.