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spriter
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Homework Statement
A single-turn square loop of side L is centered on the axis of a long solenoid. In addition, the plane of the square loop is perpendicular to the axis of the solenoid. The solenoid has 1350 turns per meter and a diameter of 5.55 cm, and carries a current of 2.20A
Homework Equations
Magnetic Field (B) of a solenoid: B = [tex]\mu_{0}[/tex]*(N/L)*I
Where [tex]\mu_{0} = 4pi * 10^{-7} T*m/A[/tex] , N/L is loops per unit length, and I is current
[tex]\Phi = B*A*Cos\theta[/tex]
The Attempt at a Solution
I tried doing this: I use the Magnetic Field of a solenoid formula to find the magnetic field through the solenoid - because I know the magnetic field within the axis of the solenoid is constant, I thought I could just find the value of that constant B and then find the flux using the other formula for the different values of L (area) - and for areas larger than the circle of the solenoid - I could take the area of the flux as the area of the circle.
However, when I put my answer in, it tells me that the answer must be expressed in terms of L (I don't know if that's supposed to be the side length of the square or if it's supposed to be the length of the solenoid).Thanks.
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