- #1
- 2,810
- 605
Consider the linear differential equation below:
[itex]
Lu=\lambda u
[/itex]
With L a hermitian operator.
We know that the eigen functions of this equation form a complete set.
So they can build every other function with their linear combination.
But from linearity of the Differential equation,we know that any linear combination of answers is also an answer so it follows that every function is a solution to this equation!
This can easily be shown to be wrong.
What's the problem?
thanks
[itex]
Lu=\lambda u
[/itex]
With L a hermitian operator.
We know that the eigen functions of this equation form a complete set.
So they can build every other function with their linear combination.
But from linearity of the Differential equation,we know that any linear combination of answers is also an answer so it follows that every function is a solution to this equation!
This can easily be shown to be wrong.
What's the problem?
thanks