- #1
mr_coffee
- 1,629
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THe directions say< indicate which fo the following statements are true and which are false, Justify your answers as best you can.
Here is the question:
[tex] \exists [/tex] x [tex]\in[/tex] R such that [tex]\forall[/tex] [tex]\in[/tex] R, x = y + 1.
I wrote the following:
There exists a real number x such that given any real number y the property x=y+1 will be true. True. y = x-1. Then y is a real number, and y + 1 = (x-1)+1 = x.
I really don't know if i did this right or not but there was an example but slighty different and the book had the following:
[tex]\forall[/tex] x [tex]\in[/tex] Z, [tex]\exists[/tex] y [tex]\in[/tex] Z such that x = y + 1.
There answer was:
Given any integer, there is an integer such that tthe first inteer is one more than the second integer. this is true. Given any integer x, take y = x-1. Then y is an integer, and y + 1 = (x-1) + 1 = x.
I'm really confused on how to go about tackling these problems. Any help would be great! thanks!
Here is the question:
[tex] \exists [/tex] x [tex]\in[/tex] R such that [tex]\forall[/tex] [tex]\in[/tex] R, x = y + 1.
I wrote the following:
There exists a real number x such that given any real number y the property x=y+1 will be true. True. y = x-1. Then y is a real number, and y + 1 = (x-1)+1 = x.
I really don't know if i did this right or not but there was an example but slighty different and the book had the following:
[tex]\forall[/tex] x [tex]\in[/tex] Z, [tex]\exists[/tex] y [tex]\in[/tex] Z such that x = y + 1.
There answer was:
Given any integer, there is an integer such that tthe first inteer is one more than the second integer. this is true. Given any integer x, take y = x-1. Then y is an integer, and y + 1 = (x-1) + 1 = x.
I'm really confused on how to go about tackling these problems. Any help would be great! thanks!