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lwaiyipl
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Homework Statement
175 cm3 of hot tea at 87°C are poured into a very thin paper cup with 80 g of crushed ice at 0°C. Calculate the final temperature of the "ice tea". (Hint: think about two processes: melting the ice into liquid and, maybe, warming the liquid.)
Homework Equations
Q=mc(deltaT)
Q=mL
The Attempt at a Solution
First, I calculated the heat loss by the tea:
Q1=(.0175)(4186)(87)=63731.9J
Then the heat needed to melt the ice:
Q2=(0.08)(33.5e4)=26800J
Heat gain by the melted ice-water
Q3=(.08)(4186)(87)=29134.6J
Then Q(final)= Q1-Q2-Q3
=7797.34J
Set it equal to the entire system
7797.34J=(0.255)(4186)(T)
My answer is 7.3 deg Celsius, which is wrong. I can't seem to find what I did wrong!
Please help! Thanks.
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