- #1
shibme
- 7
- 0
hi,
I am having trouble figuring this out mathematically...
I have no idea why but I can't figure it out using V=IR that the circuit on the left has 1/3 the current of the circuit on the right...
can anyone please give a mathematical explanation?
Left : 3Vb = I1 * RL
Right : Vb = I2 * RL
then if Vb = 2 and RL = 1, wouldn't that make I1 > I2, by 3 times..
anyone suggestions?
I am having trouble figuring this out mathematically...
I have no idea why but I can't figure it out using V=IR that the circuit on the left has 1/3 the current of the circuit on the right...
can anyone please give a mathematical explanation?
Left : 3Vb = I1 * RL
Right : Vb = I2 * RL
then if Vb = 2 and RL = 1, wouldn't that make I1 > I2, by 3 times..
anyone suggestions?