- #1
confusedaboutphysics
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need help please! what am i doing wrong??
A diver running 1.2 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 3.0 s later. How high was the cliff and how far from its base did the diver hit the water?
so does v = 1.2 m/s and t=3 seconds
i used the formula Vxo=X/t so i did 1.2=x/3 so x = 3.6m for the first part of the question. for the second part of the question i used the formula y=-1/2gt^2 so i did y=(-1/2)(-9.8)(3^2) = 44.1m.
so i said that the cliff was 3.6m high and the base was 44.1m away. but i got it wrong. am i using the right formulas?
A diver running 1.2 m/s dives out horizontally from the edge of a vertical cliff and reaches the water below 3.0 s later. How high was the cliff and how far from its base did the diver hit the water?
so does v = 1.2 m/s and t=3 seconds
i used the formula Vxo=X/t so i did 1.2=x/3 so x = 3.6m for the first part of the question. for the second part of the question i used the formula y=-1/2gt^2 so i did y=(-1/2)(-9.8)(3^2) = 44.1m.
so i said that the cliff was 3.6m high and the base was 44.1m away. but i got it wrong. am i using the right formulas?