- #1
ThomasMagnus
- 138
- 0
At what projection angle will the range of a projectile equal its maximum height?
I am having a lot of trouble with this one. Is there any way to solve this question without using double angle identities?
I know that this should be the first step:
Max height when Vy=o
Vfy2=Voy2 + 2(a)(dy)
0=(Vo2 + 2(a)(d)
Range= Vo2 sin2(theta)/g
I'm stuck here. Can anyone help me?
Thanks!
I am having a lot of trouble with this one. Is there any way to solve this question without using double angle identities?
I know that this should be the first step:
Max height when Vy=o
Vfy2=Voy2 + 2(a)(dy)
0=(Vo2 + 2(a)(d)
Range= Vo2 sin2(theta)/g
I'm stuck here. Can anyone help me?
Thanks!