- #1
Viralrush
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Homework Statement
The heat of solution of potassium acetate (KC2H3O2) in water is -15.3 kJ/mol.
If 12.7 g of KC2H3O2(s) is dissolved in 525 mL of water that is initially at 22.2 °C, what will be the final temperature (in degrees Celcius) of the resulting aqueous solution?
Homework Equations
Unsure. I used:
deltaE = C * deltaT
The Attempt at a Solution
First calculating moles: 12.7g / 98.1417g/mol = 0.1294047281 mol
Secondly, calculating kJ per mole: 0.1294047281 mol * -15.3kJ/mol = -1.97989234kJ -> -1979.89234 J
Third, sub into equation: -1979.89234J / (4.18 J/g * 537.7g) = deltaT
deltaT = -0.880897256
22.2 degrees - 0.880897256 = 21.31910274
The answer is incorrect. I use an online homework system and the following answers are incorrect:
21.3
21.2