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timeforplanb
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Electromagnetics -- parallel plate capacitor energy storage
A parallel-plate capacitor 0.5m by 1.0m has a separation distance of 2cm and a voltage difference of 10V. Find the stored energy, assuming that ε=εo. If a 200-volt potential is applied in the capacitor, (a) determine the energy stored; (b) hold d1 at 2cm and the voltage difference at 200V, while increasing d2 to 2.2cm, determine the final stored energy.
U=(1/2)(CV2)
C=εS/d
(a)
C=((8.854x10-12)(0.5x1.0))/(0.02)
C=2.2135x10-10 F
U=(1/2)(2.2135x10-10)((10+200)2)
U=4.8808x10-6 J
(b)
C=((8.854x10-12)(0.5x1.0))/(0.022)
C=2.0123x10-10 F
U=(1/2)(2.0123x10-10)((10+200)2)
U=4.4371x10-6 J
I'm not sure what to do with the voltage difference of the capacitor, so I added it with the voltage potential applied.
Homework Statement
A parallel-plate capacitor 0.5m by 1.0m has a separation distance of 2cm and a voltage difference of 10V. Find the stored energy, assuming that ε=εo. If a 200-volt potential is applied in the capacitor, (a) determine the energy stored; (b) hold d1 at 2cm and the voltage difference at 200V, while increasing d2 to 2.2cm, determine the final stored energy.
Homework Equations
U=(1/2)(CV2)
C=εS/d
The Attempt at a Solution
(a)
C=((8.854x10-12)(0.5x1.0))/(0.02)
C=2.2135x10-10 F
U=(1/2)(2.2135x10-10)((10+200)2)
U=4.8808x10-6 J
(b)
C=((8.854x10-12)(0.5x1.0))/(0.022)
C=2.0123x10-10 F
U=(1/2)(2.0123x10-10)((10+200)2)
U=4.4371x10-6 J
I'm not sure what to do with the voltage difference of the capacitor, so I added it with the voltage potential applied.
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