- #1
stratusfactio
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Homework Statement
calculate the integral f · dr for the given vector field f(x, y) and curve C:
f(x, y) = (x^2 + y^2) i; C : x = 2 + cos t, y = sin t, 0 ≤ t ≤ 2π (2pi)
Homework Equations
Would the vector F simply be <(x^2+y^2),0> since there is no j component?
The solution is 4pi and I'm getting zero.
The Attempt at a Solution
integral of C = F · dr
F = <((2+cos t)^2 + (sin t)^2),o> = <(5 + 4 cos t), 0>
dr = <-sin t, cos t>
Integral of C [0, 2pi] <(5 + 4 cos t), 0> · <-sin t, cos t> = 0 :(
I'm thinking that my error lies in the vector I'm using for F.