- #1
vu10758
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A particle position is described by position vector r = 3i + 2j and the force vector i - 2j acts on the object.
1) Find the torque about an axis through the origin and perpendicular to the xy plane. Draw the two vectors to check your torque direction.
I used the right hand rule and found out that the torque will have a negative direction. Then I used cross product term by term.
My torque is -8 k NM.
2) Find the torque about an axis through the point x = 5m, y = 5m perpendicular to the xy plane. Draw the two vectors to check your torque direction. The force should produce a roation about (5,5) consistent with your answer.
How do I do this? The answer is 7 z Nm. Do I find the torque the same way as for part 1, and then somehow take the distance between them into consideration? How come the direction is now positive?
1) Find the torque about an axis through the origin and perpendicular to the xy plane. Draw the two vectors to check your torque direction.
I used the right hand rule and found out that the torque will have a negative direction. Then I used cross product term by term.
My torque is -8 k NM.
2) Find the torque about an axis through the point x = 5m, y = 5m perpendicular to the xy plane. Draw the two vectors to check your torque direction. The force should produce a roation about (5,5) consistent with your answer.
How do I do this? The answer is 7 z Nm. Do I find the torque the same way as for part 1, and then somehow take the distance between them into consideration? How come the direction is now positive?