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thereddevils
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Homework Statement
A wooden block of mass 1.2 kg with dimensions 20cm x 10 cm x 10cm . It's resting on the surface PQYX (with base area 10cm x 10 cm , the vertical side would be 20cm in this case).What is the work done to enable it to rest on surface PQYX
Homework Equations
The Attempt at a Solution
On first thought , work done is simply the gain in potential energy ,
mgh=(1.2)(10)(0.2)=2.4 J
but that isn't the answer .