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Ken More
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At another thread under Special and General Relativity the following question was asked:
"Why isn't stellar aberration considered to be a one way measurement of c?
If the angle of aberration (θ-θ0) is -20.5 arc seconds and the Earth's orbital speed is 29.79 Kilometers/second normal to the arriving star light. The value of c should be:
c= v/tan(θ-θ0) = 29.79/9.94E-5 = 299737.98 Kilometers/second.
If more accurate values of v, θ, and the constant of aberration (≈ -20.5 arc seconds) are used why would this not confirm a one way measurement of c in the more pure vacuum of deep space?"In that thread I attempted to get a clarification of the precise meaning of Bradley's "Classical" stellar aberration model [tan (θ - θ0 ) = -v/c]. However, the participants on that thread seemed to think that I was hijacking the intent of the thread and asked me to open a new thread in astronomy because my arguments did not seem to be relevant to the measurement of c. Therefore, I am opening this thread in Astrophysics to get a clarification from the real astrophysics experts on the correct interpretation and meaning of Einstein's 1905 SRT "Relativistic" stellar aberration model as well as Bradley's "Classical" model and their relevance in determining the value of c when the precise angle θ is known by way of accurate telescopic observation from a moving point on Earth's orbit of the angle θ for a star that is known to be located at θ0 = 90° for an observer in the inertial frame of the "fixed" stars (including the sun) in our neighborhood of the milky way galaxy.
I will open the discussion with the following comment and question:
First, we must determine if the star that satisfies the Bradley “Classical” aberration model is a celestial pole star or an ecliptic pole star. If Bradley’s model is referencing an ecliptic pole star then θ0 = 90° and tan (θ - θ0) = -v/c and when c = 299737.98 Kilometers/second then θ - θ0 = -arctan v/c = -20.5 arc seconds. Would this equation then verify that c = 299737.98 Kilometers/second because an ecliptic pole star is the same “fixed” ecliptic pole star in the inertial frame of our Sun and the Earth’s ecliptic plane?
"Why isn't stellar aberration considered to be a one way measurement of c?
If the angle of aberration (θ-θ0) is -20.5 arc seconds and the Earth's orbital speed is 29.79 Kilometers/second normal to the arriving star light. The value of c should be:
c= v/tan(θ-θ0) = 29.79/9.94E-5 = 299737.98 Kilometers/second.
If more accurate values of v, θ, and the constant of aberration (≈ -20.5 arc seconds) are used why would this not confirm a one way measurement of c in the more pure vacuum of deep space?"In that thread I attempted to get a clarification of the precise meaning of Bradley's "Classical" stellar aberration model [tan (θ - θ0 ) = -v/c]. However, the participants on that thread seemed to think that I was hijacking the intent of the thread and asked me to open a new thread in astronomy because my arguments did not seem to be relevant to the measurement of c. Therefore, I am opening this thread in Astrophysics to get a clarification from the real astrophysics experts on the correct interpretation and meaning of Einstein's 1905 SRT "Relativistic" stellar aberration model as well as Bradley's "Classical" model and their relevance in determining the value of c when the precise angle θ is known by way of accurate telescopic observation from a moving point on Earth's orbit of the angle θ for a star that is known to be located at θ0 = 90° for an observer in the inertial frame of the "fixed" stars (including the sun) in our neighborhood of the milky way galaxy.
I will open the discussion with the following comment and question:
First, we must determine if the star that satisfies the Bradley “Classical” aberration model is a celestial pole star or an ecliptic pole star. If Bradley’s model is referencing an ecliptic pole star then θ0 = 90° and tan (θ - θ0) = -v/c and when c = 299737.98 Kilometers/second then θ - θ0 = -arctan v/c = -20.5 arc seconds. Would this equation then verify that c = 299737.98 Kilometers/second because an ecliptic pole star is the same “fixed” ecliptic pole star in the inertial frame of our Sun and the Earth’s ecliptic plane?
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