- #1
major_maths
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1. Find parametric equations for the line joining the points P = (1,2,-1) and Q = (5,7,5).[/b]
2. x = x0+ta
y = y0+tb
z = z0+tc
3. v = <(5-1), (7-2), (5+1)>
so v = <4,5,6> and since v is a vector in the direction of the line and should be able to be placed in the above equations in place of <a,b,c> and either of the point (P or Q) should be placed in the values of x0, y0, and z0. This should result in the final parametric equations:
x = 1+4t
y = 2+5t
z = -1+6t
This is a problem on one of my tests but my teacher marked it wrong, noting that "line PQ = <4,5,6> is the normal" and marked off 6 points out of 10. I've got no clue what I did wrong.
2. x = x0+ta
y = y0+tb
z = z0+tc
3. v = <(5-1), (7-2), (5+1)>
so v = <4,5,6> and since v is a vector in the direction of the line and should be able to be placed in the above equations in place of <a,b,c> and either of the point (P or Q) should be placed in the values of x0, y0, and z0. This should result in the final parametric equations:
x = 1+4t
y = 2+5t
z = -1+6t
This is a problem on one of my tests but my teacher marked it wrong, noting that "line PQ = <4,5,6> is the normal" and marked off 6 points out of 10. I've got no clue what I did wrong.