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ydydry
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Dear all,
I am stuck with an apparently easy system of 3 simultaneous equations that has to be solved in x,y and z. The system is the following:
##(y+z) / ((x+y+z)²)=ax^{α-1}##
##(x+z) / ((x+y+z)²)=by^{α-1}##
##(x+y) / ((x+y+z)²)=cz^{α-1}##
The parameters (a,b,c) and the variables (x,y,z) are all in ℝ₊. The parameter α is in the open interval (0,1), so that the problem is not trivial. The question is for which α there exists a closed-form solution, and for which α there exists none, given a general vector (a,b,c).
Proving that there always exist a unique solution is trivial as in each equation the right-hand sides are always increasing, whereas the left-hand sides are always decreasing in the corresponding variable (x for the first, y for the second, z for the third).
Hence, my problem is in the existence of a closed-form solution.
Many thanks!
I am stuck with an apparently easy system of 3 simultaneous equations that has to be solved in x,y and z. The system is the following:
##(y+z) / ((x+y+z)²)=ax^{α-1}##
##(x+z) / ((x+y+z)²)=by^{α-1}##
##(x+y) / ((x+y+z)²)=cz^{α-1}##
The parameters (a,b,c) and the variables (x,y,z) are all in ℝ₊. The parameter α is in the open interval (0,1), so that the problem is not trivial. The question is for which α there exists a closed-form solution, and for which α there exists none, given a general vector (a,b,c).
Proving that there always exist a unique solution is trivial as in each equation the right-hand sides are always increasing, whereas the left-hand sides are always decreasing in the corresponding variable (x for the first, y for the second, z for the third).
Hence, my problem is in the existence of a closed-form solution.
Many thanks!
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