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rum2563
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Homework Statement
A positively charged particle of mass 3.0 X 10 ^-12 kg and charge +6.4 X 10^-5 C is perpendicular to a 1.5 T magnetic field. If the particle has a speed of 4.8 X 10^3 m/s, the acceleration of the particle...?
Homework Equations
e = kg / r^2
qB = mv / r
The Attempt at a Solution
Given information:
m = 3.0 X 10 ^-12 kg
q = 6.4 X 10^-5 C
B = 1.5 T
v = 4.8 X 10^3 m/s
To find the acceleration, I started reading my book, and I found the equation:
q = mg / e
So if I rewrite this to find "g", it should be like this:
g = qe / m
BUT, I don't know e, so to find e (epsilon), I must first know the radius "r"
r = mv / qB
= (3.0 X 10 ^-12)(4.8 X 10^3) / (6.4 X 10^-5)(1.5)
= 1.5 X 10 ^-4 m
Now, I can find e:
e = kq / r^2
= (9 X 10^9)(6.4 X 10^-5) / (1.5 X 10^-4)^2
= 2.56 X 10^13 N/C
Now, I can find "g"
g = qe / m
= (6.4 X 10^-5)(2.56 X 10^13) / (3.0 X 10 ^-12)
= 5.46 X 10^20 m/s^2
But this is not the correct answer.
The correct answer should be one of the following:
3.4 X 10^-4
2.6 X 10^-20
1.5 X 10^11
1.5 X 10^-4
1.7 X 10^19
Someone please help me. I think there should be another way to do this. Please help me. Thank you.